Sodium hydrogen carbonate, on heating, produces sodium carbonate, water and carbon dioxide.
1 answer:
The mass of sodium hydrogen carbonate : 10.5 g
<h3>Further explanation</h3>Given
1.5 dm' of CO₂
1 mol gas= 24 L at RTP(25 °C, 1 atm)
Required
the mass of sodium hydrogen carbonate
Solution
Decomposition reaction of Sodium hydrogen carbonate :
2 NaHCO₃ (s) ⇒ Na₂ CO₃ (s) + H₂ O(g) + CO₂ (g)
mol CO₂ :
From the equation, mol ratio of NaHCO₃ : CO₂ (g) = 2 : 1, so mol NaHCO₃ :
Mass NaHCO₃(MW=23+1+12+3.16=84 g/mol) :
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Answer:
49.2 g/mol
Explanation:
Let's first take account of what we have and convert them into the correct units.
Volume= 236 mL x () = .236 L
Pressure= 740 mm Hg x ()= 0.97 atm
Temperature= 22C + 273= 295 K
mass= 0.443 g
Molar mass is in grams per mole, or MM= or MM=
. They're all the same.
We have mass (0.443 g) we just need moles. We can find moles with the ideal gas constant PV=nRT. We want to solve for n, so we'll rearrange it to be
n=, where R (constant)= 0.082 L atm mol-1 K-1
Let's plug in what we know.
n=
n= 0.009 mol
Let's look back at MM= and plug in what we know.
MM=
MM= 49.2 g/mol