1.How does inertia affect a person who is not wearing a seatbelt during a collision?

Irene was investigating the behavior of gases at certain conditions. Which would most likely cause an increase in the rate of co

kipiarov [429]

Answer:

Increase in temperature

Increase in pressure

Explanation:

For the rate of collisions to increase, It can happen in various ways

1. The gasses can be made to move faster: This can be done by increasing their temperature. An increase in the temperature of the gases directly relates to a corresponding increase in their kinetic energy. This means that the molecules of the gases can move with a greater velocity, which will increase collision rates.

2. The volume of the container can be reduced: Consider this; If the container is made smaller, the molecules of the gases will have less space to move about. This means that they will be bumping into the walls of the container more frequently. This reduction in volume leads to an increase in the pressure of the gas. This is exactly what happens in a piston-cylinder assembly

6 0

4 years ago

The tallest sequoia sempervirens tree in California’s redwood national parks is 111 m tall. Suppose an object is thrown downward

ch4aika [34]

The object's <u>initial velocity</u> is equal to $-10.59\frac{m}{s}$

Why?

From the statement we know the height of the tree and the time it takes to reach the ground, so, if we need to calculate its initial velocity, we can use the following formula:

$y=y_o-v_{o}*t-\frac{1}{2}g*t^{2}$

Where,

y, is the final height (0 meters in this case)

yo, is the initial height (111 meters in this case)

t, is the time elapsed (3.8 seconds in this case)

vo, is the initial speed.

g, is the acceleration due to gravity (-9.81 m/s2)

Now, let's set the origin at the top of the tree, so, rewriting the formula, we have:

$y=y_o+v_{o}*t+\frac{1}{2}g*t^{2}$

So, isolating the initial velocity, we have:

$y=y_o+v_{o}*t+\frac{1}{2}g*t^{2}$

$y=y_o+v_{o}*t+\frac{1}{2}g*t^{2}\\\\v_{o}*t=y-y_o-\frac{1}{2}g*t^{2}\\\\v_{o}=\frac{y-y_o-\frac{1}{2}g*t^{2}}{t}$

Finally, substituting and calculating, we have:

$v_{o}=\frac{-111m-0-\frac{1}{2}(-9.8\frac{m}{s^{2}}) *(3.8s)^{2})}{3.8s}\\\\v_{o}=\frac{-111m-\frac{1}{2}(-9.8\frac{m}{s^{2}})*(14.44s^{2})}{3.8s}\\\\v_{o}=\frac{-111m-\frac{1}{2}(-141.51m)}{3.8s}=\frac{-111m+70.75m}{3.8s}\\\\v_{o}=\frac{-40.25m}{3.8s}=-10.59\frac{m}{s}$

Hence, we have that the <u>initial velocity</u> of the object is $-10.59\frac{m}{s}$

Have a nice day!

7 0

4 years ago

Select all of the following that are dominant alleles.

Dennis_Churaev [7]

Answer:

D E K AND L

Explanation:

HAD TO HAVE POINTS

5 0

3 years ago

La cantidad de materia en un objeto.

Scrat [10]

La respuesta correcta es Masa

Explicación:

Todos los objetos existentes en el universo se componen de materia cuya unidad básica es conocida como átomo. A su vez el átomo se compone de subpartículas que incluyen protones, neutrones y electrones. Además de esto, la cantidad de materia o átomos en un objeto o cuerpo, por ejemplo la cantidad de materia en un balón se conoce como masa. Este factor se mide en unidades como gramos o kilos, por ejemplo, la cantidad de masa en una manzana es de aproximadamente de 150 gr. Finalmente, la masa se diferencia del peso porque en el peso la fuerza gravitacional y no solamente la materia se debe considerar.

7 0

4 years ago

The mcb of rupa's room is tripped and keeps on tripping again and again . if it is a domestic circuit, what could be the reason

kap26 [50]

Overloading

Explanation:

The reason reason why the mcb of rupa's room keeps tripping is due to the fact that excessive current has being supplied to his room.

MCB stands for a miniature circuit breaker.

A miniature circuit breaker opens up the electrical circuit by switching it off when there is overloading or faulty connections.

A MCB helps to control the flow of current and it is designed to hand certain limits of electrical voltage.
If the MCB keeps tripping, it suggests a surge in current supplied, overloading or probably a faulty connection.

learn more:

Circuit brainly.com/question/12472944

#learnwithBrainly

4 0

4 years ago