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balandron [24]
4 years ago
10

Irene was investigating the behavior of gases at certain conditions. Which would most likely cause an increase in the rate of co

llisions between gas molecules in a container?
Physics
1 answer:
kipiarov [429]4 years ago
6 0

Answer:

Increase in temperature

Increase in pressure

Explanation:

For the rate of collisions to increase, It can happen in various ways

1. The gasses can be made to move faster: This can be done by increasing their temperature. An increase in the temperature of the gases directly relates to a corresponding increase in their kinetic energy. This means that the molecules of the gases can move with a greater velocity, which will increase collision rates.

2. The volume of the container can be reduced: Consider this; If the container is made smaller, the molecules of the gases will have less space to move about. This means that they will be bumping into the walls of the container more frequently. This reduction in volume leads to an increase in the pressure of the gas. This is exactly what happens in a piston-cylinder assembly

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A ball is thrown straight up in the air. Which of these statements about its kinetic energy is true?A ball is thrown straight up
alexgriva [62]
I believe the correct answer from the choices listed above is option B. The statement that is true about the kinetic energy would be that the <span>ball has the least kinetic energy at the top of its flight. Hope this answers the question. Have a nice day.</span>
7 0
4 years ago
Read 2 more answers
What is the momentum of an object with 9.74 kg and 15 m/s?​
dolphi86 [110]

Answer: 146.1 kg/m/s

Explanation: Momentum is equal to mass times velocity, so you do 9.74 kg times 15 m/s and get 146.1 kg/m/s.

6 0
3 years ago
In a Young's double-slit experiment, a set of parallel slits with a separation of 0.114 mm is illuminated by light having a wave
elena-14-01-66 [18.8K]

Answer:

a) 2232nm

b) 2511nm

Explanation:

a) To find the path difference Δl you use the following formula:

\Delta l=m\lambda

m: order of a bright fringe

λ: wavelength of light = 558nm

for m=4:

\Delta l=(4)(558nm)=2232nm

b) The path difference for the case of destructive interference you have:

\Delta l=(m+\frac{1}{2})\lambda

m: order of a dark fringe

for m=4:

\Delta l=(4+\frac{1}{2})(558nm)=2511nm

7 0
3 years ago
An object is 10 cm from the mirror, its height is 1 cm and the focal length is 5 cm. What is the distance from the image to the
7nadin3 [17]
The answer to the question is 10
5 0
4 years ago
Read 2 more answers
An ice sled powered by a rocket engine starts from rest on a large frozen lake and accelerates at 12.7 m/s2 . At t1 the rocket e
sp2606 [1]

Answer:

The value of t₁ is 5.119 sec.

Explanation:

Given that,

Acceleration = 12.7 m/s²

Total distance D=5.85\times10^{3}\ m

Time = 94.6 sec

We need to calculate the distance

Using equation of motion

s=ut+\dfrac{1}{2}at^2

Put the value into the formula

s_{1}=0+\dfrac{1}{2}12.7t_{1}^2...(I)

We need to calculate the velocity

Using equation of motion

v=u+at

Put the value into the formula

v=0+12.7t_{1}

v=12.7t_{1}

The sled while moves with constant velocity v for time t₂

Using formula of distance

s_{2}=vt_{2}

s_{2}=12.7t_{1}t_{2}

The total distance is

s_{1}+s_{2}=5.85\times10^{3}

Put the value of s₁ and s₂

\dfrac{1}{2}12.7t_{1}^2+12.7t_{1}t_{2}=5.85\times10^{3}

6.35t_{1}+12.7t_{1}t_{2}=5.85\times10^{3}...(II)

The total time is

t_{1}+t_{2}=94.6....(III)

From equation (II) and (III)

After solving

t_{1}=5.119\ sec

Hence, The value of t₁ is 5.119 sec.

6 0
3 years ago
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