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Semenov [28]
4 years ago
12

The following items describe observational characteristics that could indicate that an object is either a white dwarf or a neutr

on star. Match each characteristic to the correct object.
•may be surrounded by a planetary nebula•emits most strongly in visible and ultraviolet•may be in a binary system that undergoes nova explosions•may be in a binary system that undergoes X-ray bursts•can have a mass of 1.5 solar masses•may be surrounded by a supernova remnant•may repeatedly dim and brighten more than once per second
Physics
1 answer:
m_a_m_a [10]4 years ago
3 0

Answer:

Brain signals are converted

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The amplitude of a sound wave is most closely
ziro4ka [17]

<u>Answer:</u> The correct answer is Option 3.

<u>Explanation:</u>

Amplitude of as sound wave is defined as the extent to which the air particles are getting displaced.

Speed of the sound wave is defined as the distance traveled by the sound wave per unit time and is not related to the amplitude of a sound wave.

Wavelength of the sound wave is defined as the difference between two crests or troughs.

Loudness of a sound wave is defined as the size of the vibration which are produced by it. This is closely related to the amplitude of the sound wave.

Pitch is defined as the sensation of the  frequency. Higher the frequency, the pitch is also high and vice-versa.

From the above information, the amplitude of a sound wave is most closely  related to the sound’s loudness.

Hence, the correct answer is Option 3.

5 0
3 years ago
Read 2 more answers
How much voltage is required to run 0.054 A of current through a 15 resistor? Use AV=IR. O A. 2.8 x 102 v O B. 1.2 V O C. 3.6 x
olga55 [171]

Answer:the answer is D

Explanation:

Plug variables in and calculate

6 0
3 years ago
Read 2 more answers
An empty glass beaker has a mass of 103 g. When filled with water, it has a total mass of 361g.
aivan3 [116]

Answer:

0.96 gcm¯³

Explanation:

From the question given above, the following data were obtained:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of beaker + oil = 351 g

Density of water = 1 gcm¯³

Density of cooking oil =?

Next, we shall determine the mass of water. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + water = 361 g

Mass of water =?

Mass of water = (Mass of beaker + water) – (Mass of empty beaker)

Mass of water = 361 – 103

Mass of water = 258 g

Next, we shall determine the volume of the beaker. This can be obtained by calculating the volume of water in the beaker.

Density of water = 1 gcm¯³

Mass of water = 258 g

Volume of water =?

Density = mass /volume

1 = 258 / volume

Cross multiply

1 × volume = 258

Volume of water = 258 cm³

Thus the volume of the beaker is 258 cm³.

Next, we shall determine the mass of the cooking oil. This can be obtained as follow:

Mass of empty beaker = 103 g

Mass of beaker + oil = 351 g

Mass of cooking oil =?

Mass of cooking oil = (Mass of beaker + oil) – (Mass of empty beaker)

Mass of cooking oil = 351 – 103

Mass of cooking oil = 248 g

Finally, we shall determine the density of the cooking oil. This can be obtained as follow:

Mass of cooking oil = 248 g

Volume of the beaker = 258 cm³

Density of cooking oil =?

Density = mass / volume

Density = 248 / 258

Density of cooking oil = 0.96 gcm¯³

7 0
3 years ago
Which of the following is NOT a method of preventing physical hazards while preparing food?
xxTIMURxx [149]
Answer: The answer is D) Keeping the food preparation area free of clutter

Explanation: TBH it just make so much sense
8 0
3 years ago
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 40.0-gram mass is attached at the 14.0-cm
sukhopar [10]

Answer:

103 g

Explanation:

given that

Mass of the attached mass, m = 40 g

Initial distance of balance, x1 = 49.7 cm = 0.497 m

Final distance of balance, x2 = 39.2 cm = 0.392 m

Equilibrium point of attachment, x3 = 14 cm = 0.14 m

To get the mass of the meter stick, we use the relation

M = m.[(x2 - x3) / (x1 - x2)]

And on solving in full, we gave

M = 40.[(0.392 - 0.14) / [0.497 - 0.392)]

M = 40(0.258 / 0.105)

M = 40 * 2.457

M = 102.8 g

Therefore the needed work good for mass of the stick j

Is 103 g

3 0
3 years ago
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