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KengaRu [80]
4 years ago
8

The mcb of rupa's room is tripped and keeps on tripping again and again . if it is a domestic circuit, what could be the reason

of phenomenon?
Physics
1 answer:
kap26 [50]4 years ago
4 0

Overloading

Explanation:

The reason reason why the mcb of rupa's room keeps tripping is due to the fact that excessive current has being supplied to his room.

MCB stands for a miniature circuit breaker.

A miniature circuit breaker opens up the electrical circuit by switching it off when there is overloading or faulty connections.

  • A MCB helps to control the flow of current and it is designed to hand certain limits of electrical voltage.
  • If the MCB keeps tripping, it suggests a surge in current supplied, overloading or probably a faulty connection.

learn more:

Circuit brainly.com/question/12472944

#learnwithBrainly

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An archer pulls her bowstring back 0.376 m by exerting a force that increases uniformly from zero to 251 N. (a) What is the equi
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Answer:

(A) 667.5 N/m

(B)

Explanation:

(A) Let the spring constant be k.

Using the formula F = kx

k = 251 / 0.376

K = 667.5 N/m

(B)

Work done

W = 0.5 × kx^2

W = 0.5 × 667.5 × 0.376 × 0.376

W = 47.2 J

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3 years ago
What is the mechanical advantage of the level shown below?
snow_lady [41]

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5 0
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Which statement about temperature is correct?
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Read 2 more answers
Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton
pishuonlain [190]

Hello!

Using Hooke's law, F spring=k delta x, find the distance a spring with an elastic constant of 4 N/cm will stretch if a 2 newton force is applied to it.

Data:

Hooke represented mathematically his theory with the equation:

F = K * Δx  

On what:

F (elastic force) = 2 N

K (elastic constant) = 4 N/cm

Δx (deformation or elongation of the elastic medium or distance from a spring) = ?

Solving:


F = K * \Delta{x}

2\:N = 4\:N/cm*\Delta{x}

4\:N/cm*\Delta{x} = 2\:N

\Delta{x} = \dfrac{2\:\diagup\!\!\!\!\!N}{4\:\diagup\!\!\!\!\!N/cm}

simplify by 2

\Delta{x} = \dfrac{2}{4}\frac{\div2}{\div2}

\boxed{\boxed{\Delta{x} = \dfrac{1}{2}\:cm}}\Longleftarrow(distance)\end{array}}\qquad\checkmark

Answer:

B.) 1/2 cm

_______________________

I Hope this helps, greetings ... Dexteright02! =)

7 0
3 years ago
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