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Maksim231197 [3]
3 years ago
12

He price of an item has been reduced by 15%. The original price was $35.

Mathematics
1 answer:
Liono4ka [1.6K]3 years ago
7 0
15% of $35 is 5.25. 35- 5.25 = $29.75
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Write the following tepeating decmial 0.35 as a fraction
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Answer:

0.35 is equal to 7/20

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What is the similarity ratio of a cube with volume 250 m3 to a cube with volume 1024 m3?
bonufazy [111]
If similarity ratio means the ratio between the lengths of the cubes:

\frac{ L_1^{3} }{ L_2^{3} } =  \frac{V_1}{V_2}  \\  \\ ratio =  \frac{L_1}{L_2} =   \frac{\sqrt[3]{V_1} }{\sqrt[3]{V_2} }
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Megan is trying to find the length of the segment using the Pythagorean Theorem
olga nikolaevna [1]

Answer:

Good for Megan but what’s the question?

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3 years ago
(3 points) Blades of grass Suppose that the heights of blades of grass are Normally distributed and independent, with each heigh
NemiM [27]

The final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

What is the normal distribution?

A continuous probability distribution for a real-valued random variable in statistics is known as a normal distribution or Gaussian distribution.

If x follows a normal distribution with mean μ and standard deviation σ then the distribution of

\sum_{i =1}^{n}x_{i}  follows an approximately normal distribution with a mean n\mu and standard deviation \sqrt{n }\sigma

let x be the height of blades of grass

x follows normal distribution with mean = μ = 4 and standard deviation = σ = 0.75.

Y = x1 + x2 +...........+x10

Y = \sum_{i =1}^{10}x_{i}

Distribution of Y is normal with,

Mean = \mu _{y}=10*4 = 40 and standard deviation = \sigma _{y}=\sqrt{10}*0.75 = 2.3717

a)

P( Y < 42.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

=NORMDIST( x, mean, SD , 1 )      

=NORMDIST(42.5, 40, 2.3717, 1 )

=0.8541

P( Y < 42.5 )  = 0.8541

b)

P( 39.5 < Y < 40.5 ) = P( Y < 40.5 ) - P( Y < 39.5 )

Using normal distribution formmula,

f(x)= {\frac{1}{\sigma\sqrt{2\pi}}}e^{- {\frac {1}{2}} (\frac {x-\mu}{\sigma})^2}

P( Y < 40.5 )  =NORMDIST(40.5, 40, 2.3717, 1 ) = 0.5835

P( Y < 39.5 ) = NORMDIST(39.5, 40, 2.3717, 1 ) = 0.4165

P( 39.5 < Y < 40.5 ) = 0.5835 - 0.4165  = 0.1670

P( 39.5 < Y < 40.5 ) = 0.1670

Hence, the final answer is:

a) P( Y < 42.5 )  = 0.8541

b) P( 39.5 < Y < 40.5 ) = 0.1670.

To learn more about the normal distribution visit,

brainly.com/question/4079902

#SPJ4

5 0
1 year ago
Multiply (n+12)(n-7)
ki77a [65]

(n+12)(n-7) = n^2 + 5n - 84

8 0
3 years ago
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