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9966 [12]
3 years ago
14

In the reaction 2H2O (l) + 2Cl– (aq) → H2 (g) + Cl2 (g) + 2OH– (aq), which substance is reduced?

Chemistry
1 answer:
Leno4ka [110]3 years ago
5 0

A. H2O is the substance reduced.

H2O + 2e^(-) →H_2 + 2OH^(-)

The substance that gains electrons is reduced.  

Remember OIL <em>RIG </em>(<em>R</em>eduction <em>I</em>s <em>G</em>ain of electrons) and

LEO the lion says <em>GER</em> (<em>G</em>ain of <em>E</em>lectrons is <em>R</em>eduction).

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There are 5.35 × 10²⁴ atoms in 8.89 moles of Helium.

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