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Ad libitum [116K]
3 years ago
10

What do Van der Waals forces do?

Chemistry
1 answer:
Greeley [361]3 years ago
3 0
Weaken London dispersion forces and stronger dipole dipole forces
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Automobile bodies contain significant amounts of iron. The iron is protected by the addition of zinc. This is called galvanizati
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<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

Galvanization is defined as the process in which a protective layer of zinc is applied to iron or steel to prevent the metal from rusting.

Zinc prevents the oxidation of iron and acts as a reducing agent in the process.

The half reaction for the process follows:

<u>Oxidation half reaction:</u>  Zn\rightarrow Zn^{2+}+2e^-

<u>Reduction half reaction:</u>  Fe^{2+}+2e^-\rightarrow Fe

Net chemical equation:  Zn+Fe^{2+}\rightarrow Zn^{2+}+Fe

Hence, the balanced chemical equation is written above.

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What are two ways in which the safe house of lean might influence a product owner?
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The safe house of lean might influence a product owner to provide better customer service.

<h3>What is the main purpose of safe house of lean?</h3>

The safe house of lean is designed to provide ultimate value to the customer one the shortest possible time.

Employing the safe house of lean might influence the product owner in the following two ways:

  • enable the product ownerr work together with Agile Teams to develop stories with clear acceptance criteria.
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Therefore, the safe house of lean might influence a product owner to provide better customer service.

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Plzz help i will give brillants and stars and thx.
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Balance the following redox equation and identify the element oxidized, the element reduced, the oxidizing agent, and the reduci
earnstyle [38]

The charge of Br changed from –1 to 0, therefore it is the element which is oxidized. Since it is oxidized then Br is also the reducing agent.

 

The charge of Mn changed from +4 to +2 therefore it is the element which is reduced. Since Mn is reduced, then MnO2 is the oxidizing agent.

 

The half –reactions are:

Br: 2Br --> Br2 + 2e-

Mn: MnO2 --> Mn2+

First balance oxygen by adding H2O:

MnO2 --> Mn2+ + 2H2O

Then balance hydrogen by adding H+ ions:

4H+ + MnO2 --> Mn2 + 2H2O

Then the appropriate electrons:

4e- + 4H+ + MnO2 --> Mn2 + 2H2O

 

Multiply the half-reaction of Br by 2 because the half-reaction of Mn has 4 electrons.

4Br --> 2Br2 + 4e-

 

Combine the two half reactions and cancel common factors:

4Br-  +  4H+  +  MnO2 --> 2Br2  +  Mn2  +  2H2O

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