Hello!
The answer is: Al2S3(s)+6H2O(l)→2Al(OH)3(s)+3H2S(g)
Why?
Balancing equations is the process where we look for an equal number atoms for each element on both sides of a chemical reaction (reactants and products) in order to satisfy the Law of Conservation of Mass, which states that the mass is equal before and after the reaction.
So, we have to check the number of atoms for both sides of the reaction:
Reactants:
Al=2 atoms
S= 3 atoms
H= 2 atoms
O = 1 atom
Products:
Al = 2 atoms
O = 6 atoms
H = 6 + 6 atoms = 12 atoms
S= 3 atoms
So, we can see that there is a difference between the number of atoms of Hydrogen, there are 2 atoms for the reactants and 12 for the products, for the Oxygen we can see that there is just 1 atom for the reactants and 6 for the products.
To adjust the number of atoms of Hydrogen and Oxygen, we just need to multiply the compound by 6 (H2O)
Al2S3(s)+6H2O(l)→2Al(OH)3(s)+3H2S(g)
Therefore, we have the same number of atoms for each element on both sides of the chemical reaction.
Have a nice day!
Answer:
f) is the answer please thanks
57.167days will be required for 4.68g to remain
You should clean up after every investigation because if you leave a mess, maybe another detective will come in and get lost because of the mess you left.
The percent yield of this reaction is calculated as follows
Mg3N2 + 3H2O =2NH3 + 3Mgo
calculate the theoretical yield,
moles=mass/molar mass
moles Mg3N2= 3.82 g/100g/mol= 0.0382 moles(limiting regent)
moles of H2o= 7.73g/18g/mol = 0.429 moles ( in excess_)
by use of mole ratio between Mg3N2 to MgO which is 1:3 the moles of MgO = 0.0382 x3 = 0.1146 moles
mass =moles x molar mass
the theoretical mass is therefore = 0.1146mole x 40 g/mol = 4.58 grams
The % yield = actual mass/theoretical mass x1000
= 3.60/4.584 x100= 78.5%