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3 years ago

8

Sue and Kim earn $52 per week for delivering magazines. Sue worked for x weeks and earned an additional total bonus of $12. Kim

worked for y weeks. Which expression shows the total money, in dollars, that sue and Kim earned for delivering magazines?

2 answers:

Ivahew [28]3 years ago

3 0

64x + 52y 52x − 12 + 52y 52x + 64y 52x + 12 + 52y

aalyn [17]3 years ago

3 0

Mmmmmmm I would say the equation is y = 52x + 12 because 52 dollars per week is the slope, 12 dollars is the extra so it will be b in the equation y = mx + b. So you will end up with y = 52x +12. :)

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Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

7 0

3 years ago

What is the point-slope form of a line with slope 3/2 that contains the point (-1 2)

Drupady [299]

Answer:

The point-slope form of this equation is y - 2 = 3/2(x + 1)

Step-by-step explanation:

To find the answer to any equation in point slope form, start with the base form of the equation.

y - y1 = m(x - x1)

Now input the slope for m and the point at (x1, y1)

y - 2 = 3/2(x + 1)

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3 years ago

(19,-9) (-7,-15) in slope intercept form

never [62]

Answer:

$y=\frac{3}{13}x-\frac{174}{13}$

Step-by-step explanation:

slope:

$m=\frac{-15-(-9)}{-7-19} =\frac{-15+9}{-26} =\frac{-6}{-26} =\frac{3}{13}$

Equation, with the point (19, -9):

$y-(-9)=\frac{3}{13} (x-19)$

$y+9=\frac{3}{13} x-\frac{57}{13}$

$y=\frac{3}{13} x-\frac{57}{13} -9$

$-9=-9(\frac{13}{13} )=-\frac{117}{13}$

$y=\frac{3}{13}x-\frac{174}{13}$

Hope this helps

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sergiy2304 [10]

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