For this case we must solve the following equation:

If we apply cubic root to both sides of the equation, then we eliminate the exponent on the left side:
![\sqrt [3] {x ^ 3} = \sqrt [3] {22}\\x = \sqrt [3] {22}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7Bx%20%5E%203%7D%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%5C%5Cx%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D)
That is the exact solution of the equation. Its decimal solution is given by:
![x = \sqrt [3] {22} = 2.8020](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%20%3D%202.8020)
ANswer:
The solution to the equation is ![x = \sqrt [3] {22} = 2.8020](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%20%5B3%5D%20%7B22%7D%20%3D%202.8020)
Answer:
y = 5.2
Step-by-step explanation:
x : y = 5 : ?
Given that x = 5
So,
<u><em>Condition:</em></u>
y = 20% + x
y = 
y = 
y = 5.2
Answer:
$5.75
Step-by-step explanation:
First we will make an equation. We will put child tickets as x, and adult tickets as x+3.50. =
2x+7+3x=35.75=
5x=28.75
x=5.75
Answer:
D
Step-by-step explanation:
We know it has 2 distinct zeros. This means the discriminant of the quadratic is positive and must have 2 real zeros that can be rational or irrational. We also know the quadratic has rational coefficients which means both are either rational or irrational. They can not be one of either. Since it tells us one is rational, the other must be too.