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4 years ago

Explain Alfred wegener's hypothesis

1 answer:

8 0

He proposed the theory of Continental Drift. He believed that all of the continents were once joined together in a super continent he called Pangea (not sure if that's spelled right I studied this awhile ago). He proved this by showing similarities in fossils in completely different continents and showing how well the continents could fit together.

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A student stretches a spring, attaches a 1.20 kg mass to it, and releases the mass from rest on a frictionless surface. The resu

Sphinxa [80]

Answer:

the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

Explanation:

Given that;

mass of the object m = 1.20 kg

period of oscillation = 0.750 s

Amplitude ( A/x) = 15.0 cm = 0.15 m

now;

a) Determine the oscillation frequency;

oscillation frequency f = 1/T

we substitute

f = 1 / 0.750 s

f = 1.33 Hz

Therefore, the oscillation frequency is 1.33 Hz

b) Determine the spring constant;

we solve for spring constant from the following expression;

T = 2π√(m/k)

k = 4π²m / T²

so we substitute

k = (4π² × 1.20) / (0.750)²

k = 47.3741 / 0.5625

k = 84.22 N/m

Therefore, the spring constant is 84.22 N/m

c) determine the speed of the mass when it is halfway to the equilibrium position

So, at equilibrium, the energy is equal to K.E

such that;

1/2mv² = 1/2kx²

mv² = kx²

v² = kx² / m

v = √( kx²/m)

we substitute

v = √( 84.22×(0.15 m)²/ 1.2 )

v = √( 1.89495 / 1.2 )

v = √ 1.579125

v = 1.26 m/s

Therefore, the speed of the mass when it is halfway to the equilibrium position is 1.26 m/s

3 0

3 years ago

Water moves from Earth's surface to the atmosphere and back to Earth's surface again in a process known as the water cycle. Whic

marysya [2.9K]

One of the major forms of energy driving the water cycle is geothermal energy. Heat is responsible for warming up water, which in turn evaporates, and then again returns to Earth's surface in the form of rain.

5 0

4 years ago

Read 2 more answers

A 2 kg blue car is moving 6 m/s to the right and collides with a 3 kg red car that is moving 2 m/s to the left. The cars collide

snow_lady [41]

Answer:

Their velocity after the collision is 1.2 m/s, to the right.

Explanation:

Given;

mass of the blue car, m₁ = 2 kg

initial velocity of the blue car, u₁ = 6 m/s

mass of the red car, m₂ = 3 kg

initial velocity of the red car, u₂ = 2 m/s

let the blue car moving to the right be in positive direction

also, let the red car moving to the left be in negative direction

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ - m₂u₂ = v(m₁ + m₂)

where;

v is their velocity after the collision

(2 x 6) - (3 x 2) = v(2 + 3)

12 - 6 = 5v

6 = 5v

v = 6/5

v = 1.2 m/s, to the right

Therefore, their velocity after the collision is 1.2 m/s, to the right.

7 0

3 years ago

A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal fri

zhannawk [14.2K]

Answer:

The speed of the knife after passing through the target is 9.33 m/s.

Explanation:

We can find the speed of the knife after the impact by conservation of linear momentum:

$p_{i} = p_{f}$

$m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}}$

Where:

$m_{k}$ : is the mass of the knife = 22.5 g = 0.0225 kg

$m_{t}$ : is the mass of the target = 300 g = 0.300 kg

$v_{i_{k}}$ : is the initial speed of the knife = 40.0 m/s

$v_{i_{t}}$ : is the initial speed of the target = 2.30 m/s

$v_{f_{k}}$ : is the final speed of the knife =?

$v_{f_{t}}$ : is the final speed of the target = 0 (it is stopped)

Taking as a positive direction the direction of the knife movement, we have:

$m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}}$

$v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s$

Therefore, the speed of the knife after passing through the target is 9.33 m/s.

I hope it helps you!

4 0

3 years ago

The Robinson projection map is considered very useful because

Vladimir79 [104]

Hello,
The question states: <span>The Robinson projection map is considered very useful because...
The answer is $\boxed{because \ most \ distances, \ sizes, \ and \ shapes \ are \ accurate.}$

Hope this helped!

~FoodJunky
</span>

7 0

4 years ago