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castortr0y [4]
3 years ago
13

A model rocket is fired vertically upward from rest. Its acceleration for the first three seconds is a(t) = 66 t, at which time

the fuel is exhausted and it becomes a freely "falling" body. 15 seconds later, the rocket's parachute opens, and the (downward) velocity slows linearly to -23 ft/s in 5 s. The rocket then "floats" to the ground at that rate.
Determine the position function s and the velocity function v (for all times t).
Physics
1 answer:
musickatia [10]3 years ago
5 0

(x=yt-2)^2(56-tea)^2x10r

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With the aid of a string, a gyroscope is accelerated from rest to 32 rad/s in 0.40 s. What is its angular acceleration in rad/s2
Irina-Kira [14]
<h2>Angular acceleration is 80 rad/s² </h2><h2>Number of revolutions undergone is 1.02</h2>

Explanation:

We have equation of motion v = u + at

     Initial angular velocity, u = 0 rad/s

     Final angular velocity, v = 32 rad/s    

     Time, t = 0.40 s

     Substituting

                      v = u + at  

                      32 = 0 + a x 0.40

                      a = 80 rad/s²

     Angular acceleration is 80 rad/s²

  We have equation of motion s = ut + 0.5 at²

        Initial angular velocity, u = 0 rad/s

        Angular acceleration, a = 80 rad/s²

        Time, t = 0.4 s      

     Substituting

                      s = ut + 0.5 at²

                      s = 0 x 0.4 + 0.5 x 80 x 0.4²

                      s = 6.4 rad

      Angular displacement  = 6.4 rad

     \texttt{Number of revolutions = }\frac{6.4}{2\pi}=1.02

Number of revolutions undergone is 1.02

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3 years ago
How to do this problem
marusya05 [52]
The answer I'm pretty sure is 3
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If the absolute pressure of a gas is 550.280 kPa, its gage pressure is
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If the absolute pressure of a gas is 550.280 kPa, its gage pressure is <span> a. 101.325 kPa.
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Answer:

Hey Friend....

Explanation:

This is ur answer....

<h3><em>Transfer of energy by electromagnetic waves. Radiation doesn't require matter. Sunlight melting a wax crayon left outside is radiation.</em></h3><h3><em /></h3>

Hope it helps!

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Follow me! :)

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