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s2008m [1.1K]
3 years ago
6

Display the cost of landscaping a backyard with sod that is sold by the square foot and fencing that is sold by the foot. The in

put will be the length and width of the backyard, the price of sod per square foot and the price of fencing per foot.
Computers and Technology
1 answer:
Ipatiy [6.2K]3 years ago
7 0

Answer:

length = float(input("Enter length of the backyard in foot: "))

width = float(input("Enter width of the backyard in foot: "))

sod_price = float(input("Enter the price of sod per square foot: "))

fencing_price = float(input("Enter the price of fencing per foot: "))

area = length * width

perimeter = 2 * (length + width)

cost = sod_price * area + fencing_price * perimeter

print("The cost of landscaping is $" + str(cost))

Explanation:

*The code is in Python.

Ask the user to enter the length, width, sod_price, and fencing_price

Calculate the area and perimeter of the backyard

Calculate the cost, sod_price * area + fencing_price * perimeter

Print the cost

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5 0
3 years ago
give one word • pressure exerted by a stationary liquid _______. • force in a direction perpendicular to a given surface area __
mel-nik [20]

Answer:

1. Hydrostatic pressure.

2. Pressure.

3. Equilibrium forces.

Explanation:

1. <u>Hydrostatic pressure</u>: pressure exerted by a stationary liquid. It is simply the pressure in a liquid such as water at a specific depth.

Mathematically, hydrostatic pressure is given by the formula;

H.P = rho * g * d

Where:

  • H.P is the hydrostatic pressure of a liquid.
  • rho represents the density of a liquid.
  • g is the acceleration due to gravity.
  • d is the depth (height) of a liquid.

2. <u>Pressure</u>: it is the force in a direction perpendicular to a given surface area. Thus, it's typically measured in Newton per meters (N/m²).

Mathematically, pressure is given by the formula;

Pressure = \frac {Force}{area}

3. <u>Equilibrium forces</u>: a pair of forces whose resultant is zero. It is also referred to as balanced forces because the resultant of all the pair of forces acting on a body or system is at equilibrium (balanced).

6 0
3 years ago
Which statement about dialogues is NOT correct? Select one: A. Users should be able to control the direction of speed of dialogu
Gennadij [26K]

Answer:

Option B is not correct

Explanation:

Dialogues become problematic when they appear automatically because of high level incompatibility

3 0
3 years ago
Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

Quadratic()//defining default constructor

{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

{

this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

{

this->a = a;//assigning value in a variable

}

double getB() //defining a get method  

{

return b;//return value b

}

void setB(double b)//defining a set method to hold value in parameter  

{

this->b = b;//assigning value in b variable

}

double getC() //defining a get method

{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

{

return ((a*x*x)+(b*x)+c);//return evaluated value

}

double numberOfReal()//defining a method numberOfReal to calculates the real roots

{

return (b*b)-(4*a*c);//return real roots

}

void findroots()//defining a method findroots

{

double d=numberOfReal();//defining double variable to hold numberOfReal method value

if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

if(r1==r2)//defining if block to check r1 equal to r2

cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

else//else block

cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value

}

}

void print()//defining a method print  

{

cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation

}

};

int main()//defining main method  

{

Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor

q.print();//calling print method

cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value

q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

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