Momentum is Mass times Velocity
Answer:
The arrow will leave the bow with a velocity of 10 m/s.
Explanation:
Hi there!
The potential energy stored in the bow can be calculated using the following equation:
U = 1/2 · k · d²
Where
U = elastic potential energy.
k = spring constant.
d = stretched distance of the bow
Then:
U = 1/2 · 112 N/m · (0.29 m)²
U = 4.7 J
When the bow is released, the potential energy is transformed into kinetic energy. Then, the kinetic energy of the arrow when it leaves the bow will be:
KE = 1/2 · m · v² = 4.7J
Where:
KE = kinetic energy.
m = mass of the arrow.
v = velocity of the arrow:
Then:
4.7 J = 1/2 ·0.094 kg · v²
2 · 4.7 J / 0.094 kg = v²
9.4 kg · m²/s² / 0.094 kg = v²
v = 10 m/s
The arrow will leave the bow with a velocity of 10 m/s.
Answer:
When you slide an object there is less friction than when you roll it. an object's acceleration (change in speed) depends on the mass of the object and the amount of force applied on it. an object at rest stays at rest unless a force acts on it. ... A ball rolling on grass has more friction than a ball rolling on tile.
In physical chemistry or in thermodynamics, the work done on the system or by the system (depending on the sign convention) can be determined in several ways. When assumptions like ideal gas behavior is applied, then the formula for work is
W = Δ(PV)
which is the change of the product of Pressure and Volume. But since it was specified that Pressure is constant, the work could be simplified into
W = PΔV = P(V₂ - V₁)
Since we already know the constant pressure and the volumes of the ideal gas before and after the change, we could now solve for work. But let's establish first the units of work which is in Joules. When simplified, Joules is equal to m³*Pa. So, we first change the unit of pressure from atm to Pascals ( 1 atm = 101,325 Pa) and the unit of volume from liters to m³ (1 m³ = 1000 L),
1.5 atm * 101325 Pa/1 atm = 151987.5 Pa
15 L * 1 m³/1000 L = 0.015 m³
35 L * 1 m³/1000 L = 0.035 m³
Then, they are now ready for substitution,
W = 151987.5 Pa (0.035 m³ - 0.015 m³)
W = 3,039.75 Joules
As the charges’ distance increase, there is a weaker force of attraction between them hence the electrostatic force decreases as distance increases. It increase by 4 (times 4) so the force will decrease by 4 making the answer
=A (400 divided by 4 = 100)