less mass is more mass but less energy in more mass. less mass has more energy
Answer:
6.0 ×
W/![m^{2}](https://tex.z-dn.net/?f=m%5E%7B2%7D)
Explanation:
From Wien's displacement formula;
Q = e A![T^{4}](https://tex.z-dn.net/?f=T%5E%7B4%7D)
Where: Q is the quantity of heat transferred, e is the emissivity of the surface, A is the area, and T is the temperature.
The emissive intensity =
= e![T^{4}](https://tex.z-dn.net/?f=T%5E%7B4%7D)
Given from the question that: e = 0.6 and T = 1000K, thus;
emissive intensity = 0.6 × ![(1000)^{4}](https://tex.z-dn.net/?f=%281000%29%5E%7B4%7D)
= 0.6 × 1.0 × ![10^{12}](https://tex.z-dn.net/?f=10%5E%7B12%7D)
= 6.0 ×
![\frac{W}{m^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BW%7D%7Bm%5E%7B2%7D%20%7D)
Therefore, the emissive intensity coming out of the surface is 6.0 ×
W/
.
27.9 idkkkk look it up on photomath
Answer:
471392.4 N
Explanation:
From the question,
Just before contact with the beam,
mgh = Fd.................... Equation 1
Where m = mass of the beam, g = acceleration due to gravity, h = height. F = average Force on the beam, d = distance.
make f the subject of the equation
F = mgh/d................ Equation 2
Given: m = 1900 kg, h = 4 m, d = 15.8 = 0.158 m
Constant: g = 9.8 m/s²
Substitute into equation 2
F = 1900(4)(9.8)/0.158
F = 471392.4 N
Metallic bonds! Hope this helps!! :))