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Alchen [17]
4 years ago
8

You find a pressure gauge in the lab and the spec sheet says that the maximum pressure it can read a maximum of 2 inches of wate

r. What is the maximum pressure in pascals?
Physics
1 answer:
Inessa05 [86]4 years ago
8 0

Answer:

Maximum pressure in pascal is 497.84 pa

Explanation:

Pressure is given by P=\rho g h

where \rho is density of water = 1000kg/m^3

height of the water h is 2 inches = 2\times 25.4=50.8 mm=50.8\times 10^{-3} m

Maximum pressure in pascal is

P=1000\times 9.8\times 50.8\times 10^{-3}\\p=497.84 Pa

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Answer:

a) and c).

Explanation:

For a complete destructive interference occur, it must be met the following condition relating the wavelength, and the difference in the paths taken by the sound emitted by the sources until arriving to the listening point:

d = |dA- dB| = (2n-1)*(λ/2)

For n= 1,  d = λ/2 = 0.25 m, it doesn't meet any of the cases.

For n=2, d= 3*(λ/2) = 0.75 m

In the case a) we have dA = 2.15 m and dB = 3.00 m, so dB-dA = 0.75 m, which means that in the location stated by case a) a complete destructive interference would occur.

For n=3, d= 5*(λ/2) = 5*0.25 m = 1.25 m.

This is just the case c) because we have dA = 3.75 m and dB = 2.50 m, so dA-dB = 1.25 m, which means that in the location stated by case c) a complete destructive interference would occur also.

The remaining cases don't meet the condition stated above, so the statements found to be true are a) and c),

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4 years ago
From the small number of impact craters on ____, planetary geologists suspect that virtually all its original surface has been c
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<span>From the small number of impact craters on moon, planetary geologists suspect that virtually all its original surface has been covered over by younger volcanic activity</span>. Most of the Moon's surface is densely covered with craters, but we find relatively few craters within the lunar maria.<span> </span>

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GaryK [48]

Answer:

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Explanation:

7 0
3 years ago
Read 2 more answers
A body on the surface of a planet with the same radius as Earths weighs 10 times more than it does on Earth. What is the mass of
nadya68 [22]

Answer:

Explanation:

Given

radius of Planet is equal to radius of Earth

r_p=r_e

Weight of body on Planet F_p=mg_p

where m=mass of body

g_p=acceleration\ due\ to\ gravity\ on\ surface\ of\ Planet

Weight of body on earth F_e=mg_e

g_e=acceleration\ due\ to\ gravity\ on\ Earth

acceleration due to gravity is given by

g=\frac{GM}{r^2}

where G=gravitational constant

M=mass of Planet

r=radius of planet

for earth g_e=\frac{GM_e}{r_e^2}

for planet g_p=\frac{GM_p}{r_p^2}

substituting these values in F_e and F_p

F_p=m\times \frac{GM_p}{r_p^2}---1

F_e=m\times \frac{GM_e}{r_e^2}---2

divide 1 and 2

\frac{F_p}{F_e}=\frac{m\times \frac{GM_p}{r_p^2}}{m\times \frac{GM_e}{r_e^2}}

10=\frac{M_p}{M_e}

M_p=10M_e

6 0
3 years ago
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