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Alchen [17]
3 years ago
8

You find a pressure gauge in the lab and the spec sheet says that the maximum pressure it can read a maximum of 2 inches of wate

r. What is the maximum pressure in pascals?
Physics
1 answer:
Inessa05 [86]3 years ago
8 0

Answer:

Maximum pressure in pascal is 497.84 pa

Explanation:

Pressure is given by P=\rho g h

where \rho is density of water = 1000kg/m^3

height of the water h is 2 inches = 2\times 25.4=50.8 mm=50.8\times 10^{-3} m

Maximum pressure in pascal is

P=1000\times 9.8\times 50.8\times 10^{-3}\\p=497.84 Pa

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Argon makes up 0.93% by volume of air. Calculate its solubility (in mol/L) in water at 20°C and 1.0 atm. The Henry's law constan
vladimir2022 [97]

Answer:

S= 1.40x10⁻⁵mol/L

Explanation:

The Henry's Law is given by the next expression:

S = k_{H} \cdot p (1)

<em>where S: is the solubility or concentration of Ar in water, k_{H}: is Henry's law constant and p: is the pressure of the Ar </em>

<u>Since the argon is 0.93%, we need to multiply the equation (1) by this percent:</u>

S = 1.5 \cdot 10^{-3} \frac{mol}{L\cdot atm} \cdot 1.0atm \cdot \frac{0.93}{100} = 1.40 \cdot 10^{-5} \frac{mol}{L}

Therefore, the argon solubility in water is 1.40x10⁻⁵mol/L.

Have a nice day!          

8 0
3 years ago
Which molecule will undergo only london dispersion forces when interacting with other molecules of the same kind?
vfiekz [6]

Explanation:

London dispersion forces will form between non-polar molecules(polar ) that are symmetrical  like O₂, H₂, Cl₂ and noble gases.

  • The attraction here is because non-polar molecules becomes polar due to the constant motion of its electrons.
  • This lead to an uneven charge distribution at an instant.
  • A temporary  dipole or instantaneous dipole forms.
  • The temporary dipole can induce neighboring molecules to be distorted and forms dipoles as well.
  • This forms london dispersion forces.

Learn more:

Intermolecular forces brainly.com/question/10602513

#learnwithBrainly

7 0
3 years ago
What is the work-energy theorem equation?
grin007 [14]

Answer:

W = Fd = KE =1/2mv²

Explanation:

not sure if that's what your looking for but i'm pretty sure this is it.

7 0
3 years ago
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A uniform horizontal rod of mass Mand length rotates with angular velocity about a vertical axis through its center. Attached to
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Answer:

     o

90

Explanation:

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3 years ago
to start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of 290 m/s at 53.0° above the ho
kap26 [50]
So this is easy to calculate when you split the velocity into x and y components. The x component is going to equal cos(53) * 290 and the y component is going to equal sin(53)*290.

The x location therefore is 290*cos(53)*35 = 6108.4m

The y location needs to factor in the downwards acceleration of gravity too, which is 9.81m/s^2. We need the equation dist. = V initial*time + 0.5*acceleration*time^2.

This gives us d=290*sin(53)*35 + (0.5*-9.81*35^2)=2097.5m

So your (x,y) coordinates equals (6108.4, 2097.5)
5 0
3 years ago
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