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Alchen [17]
3 years ago
8

You find a pressure gauge in the lab and the spec sheet says that the maximum pressure it can read a maximum of 2 inches of wate

r. What is the maximum pressure in pascals?
Physics
1 answer:
Inessa05 [86]3 years ago
8 0

Answer:

Maximum pressure in pascal is 497.84 pa

Explanation:

Pressure is given by P=\rho g h

where \rho is density of water = 1000kg/m^3

height of the water h is 2 inches = 2\times 25.4=50.8 mm=50.8\times 10^{-3} m

Maximum pressure in pascal is

P=1000\times 9.8\times 50.8\times 10^{-3}\\p=497.84 Pa

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During the first 14 minutes of a 1.0 hour trip, a car has an average speed 36 km/h. What must the average speed in km/h of the c
oksian1 [2.3K]

Answer:

85.5 km/h

Explanation:

t_{1} = time interval for first phase = 14 min = \frac{14}{60} h = 0.233 h

t_{2} = time interval for second phase = 46 min = \frac{46}{60} h = 0.767 h

v = average speed for the entire trip = 74 km/h

v_{1} = average speed in first phase = 36 km/h

v_{2} = average speed in second phase

d_{1} = distance traveled in first phase

d_{2} = distance traveled in first phase

average speed is given as

v = \frac{d_{1} + d_{2}}{t_{1} + t_{2}}

v = \frac{v_{1} t_{1} + v_{2} t_{2}}{t_{1} + t_{2}}

74 = \frac{(36) (0.233) + v_{2} (0.767)}{0.233 + 0.767}

74 = (36) (0.233) + v_{2} (0.767)

v_{2} = 85.5 km/h

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3 years ago
18.5 miles per second (30 km/sec). Choose the Earth movement that best relates to this description.
Vladimir79 [104]

Answer:

Earth orbits the SUn

Explanation:

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Two particles are separated by 0.38 m and have charges of -6.25 x 10-°C
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Whats the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s
Vesnalui [34]

Answer:

600J

Explanation:

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A large power plant heats 1917 kg of water per second to high-temperature steam to run its electrical generators.
erastova [34]

Complete Question

A large power plant heats 1917 kg of water per second to high-temperature steam to run its electrical generators.

(a) How much heat transfer is needed each second to raise the water temperature from 35.0°C to 100°C, boil it, and then raise the resulting steam from 100°C to 450°C? Specific heat of water is 4184 J/(kg · °C), the latent heat of vaporization of water is 2256 kJ/kg, and the specific heat of steam is 1520 J/(kg · °C).

J

(b) How much power is needed in megawatts? (Note: In real power plants, this process occurs under high pressure, which alters the boiling point. The results of this problem are only approximate.)

MW

Answer:

The heat transferred is  Q = 5.866 * 10^9 J

The power is  P = 5866\  MW

Explanation:

From the question we are told that

      Mass of the water per second is m = 1917 \ kg

      The initial temperature of the water is T_i  = 35^oC

      The boiling point of water is  T_b = 100^oC

      The final temperature T_f = 450^oC

      The latent heat of vapourization of water is  c__{L}} = 2256*10^3 J/kg

      The specific heat of water c_w = 4184 J/kg^oC

      The specific heat of stem is C_s =1520 \ J/kg ^oC

Generally the heat needed each second is mathematically represented as

         Q = m[c_w (T_i - T_b) + m* c__{L}}  + m* c__{S}} (T_f - T_b)]

Then substituting the value

        Q = m[c_w [T_i - T_b] + c__{L}}  + C__{S}} [T_f - T_b]]

         Q = 1917 [(4184) [100 - 35] + [2256 * 10^3]  +[1520]  [450 - 100]]

         Q = 1917 * [3.05996 * 10^6]

         Q = 5.866 * 10^9 J

The power required is mathematically represented as

         P = \frac{Q}{t}

From the question t = 1\ s

So  

        P = \frac{5.866 *10^9}{1}

        P = 5866*10^6 \ W

        P = 5866\  MW

6 0
3 years ago
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