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Yakvenalex [24]
4 years ago
13

If both mass and speed are doubled, what happens to its momentum?

Physics
1 answer:
puteri [66]4 years ago
7 0

The general formula is:      Momentum = (mass) x (speed)

I never like to just write a bunch of algebra without explaining it.
But in this particular case, there's really not much to say, and
I think the algebra will pretty well explain itself.  I hope so:


Original momentum = (original mass) x (original speed)


New momentum = (2 x original mass) x (2 x original speed)

                           = (2) x (original mass) x (2) x (original speed)

                           = (2) x (2) x (original mass) x (original speed)

                           =  (4) x (original mass) x (original speed)

                           =  (4) x (original momentum).

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On a straight road (taken to be in the x direction) you drive for an hour at 60 km per hour, then quickly speed up to 120 km per
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Answer:

The average velocity is 180 km/hr

Explanation:

Given;

initial velocity, u = 60 km per hour

final velocity, v = 120 km per hour

initial time = 1 hour

final time = 2 hour

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final position = 120 km/h x 2 hour = 240 km

The average velocity is given by;

V_{avg} = \frac{Final \ position\  - \ Initial \ position}{final \ time\  - \ initial \ time}\\\\V_{avg} = \frac{240km \ - \ 60km}{2hr\  - \ 1hr} \\\\V_{avg} = \frac{180 \ km}{1hr} \\\\V_{avg}= 180 \ km/hr

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3 0
3 years ago
In contact forces, _____.
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Explanation:
8 0
3 years ago
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Oxygen Supply in Submarines Nuclear submarines can stay under water nearly indefinitely because they can produce their own oxyge
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Answer:

1.865 * 10^-4 L

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A 0.280-kg croquet ball makes an elastic head-on collision with a second ball initially at rest. The second ball moves off with
Jet001 [13]

Answer:

mass of second ball is 0.84 kg

Explanation:

mass of ball = 0.280 kg

to find out

mass of the second ball

solution

we know here elastic head on collision and

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we consider here m1 mass of 1st ball and m2 mass of second ball

v1 = velocity of first ball before collision

v2 = velocity of second ball before collision

v3 = velocity of first ball after collision

v4 = velocity of second ball after collision

so here

we know 2nd ball was on rest so v2 = 0

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m1v1 + m2(0) = m1(-v1/2) + m2(v1/2)

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