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Zina [86]
4 years ago
11

A new roller coaster contains a loop-the-loop in which the car and rider are completely upside down. If the radius of the loop i

s 13.2 m, with what minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top? Assume the rider is not strapped to the car.
Physics
1 answer:
Alla [95]4 years ago
6 0

To solve this problem it is necessary to apply the concepts related to gravitational force and centripetal force,

By definition the gravitational force on earth is defined under Newton's second law where,

F_g = mg

Where,

m = mass

g = Gravity acceleration

At the same time we know that the Centripetal force is equivalent to

F_c = \frac{mv^2}{r}

Where,

m = mass

v = Velocity

r = Radius

Since there is a balance between the two, you have to

F_g = F_c

mg = \frac{mv^2}{r}

Re-arrange to find the velocity we have,

v = \sqrt{rg}

v = \sqrt{13.2*9.8}

v = 11.37m/s

Therefore the minimum speed must be 11.37m/s

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