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Sloan [31]
2 years ago
6

The word "static" means A sticky B rough C not moving

Physics
1 answer:
nirvana33 [79]2 years ago
4 0

Answer:

not moving

static actually means lacking in movement or action❤

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What is the magnetic force on a proton that is moving at 2.5 107 m/s to the left through a magnetic field that is 3.4 T and poin
evablogger [386]

Answer: C. 1.4 10-11 N up

Explanation:

The magnetic force, F on a charge q moving with velocity v in a magnetic field B at an angle θ is given by:

F = q v B sin θ

Charge of proton, q = 1.6 × 10⁻¹⁹ C

Strength of magnetic field, B = 3.4 T pointing outwards

velocity of the proton, v = 2.5 × 10⁷ m/s towards left

Magnetic force is given by:

F =  1.6 × 10⁻¹⁹ C× 2.5 × 10⁷ m/s ×3.4 T× sin 90 = 13.6 × 10⁻¹² N = 1.4 × 10⁻¹¹ N up

The direction of the force is given by Lorentz Right hand rule. The fingers point magnetic field, the thumb points towards velocity, then the force on the proton is given by the direction perpendicular to the palm.  

The magnetic field acts outwards with velocity of the proton towards left. The force would act perpendicular to the two -upwards.

6 0
3 years ago
A person will feel weightless whenever?
gavmur [86]
When your'e in space you feel weightless blc there's no grsvity in space.
5 0
4 years ago
Read 2 more answers
How much heat is absorbed by 60 g of copper when it is heated from 20°C to 80°C?
ira [324]

Answer:

1,836J

Explanation:

6 0
4 years ago
Define Standard Unit​
Vinvika [58]

answer:

standard units are the units we usually use to measure the weight, length or capacity of objects.

explanation:

  • international system of units or SI units are standard units
  • these units used for measuring quantities are accepted worldwide
  • for example: kilogram is standard unit for mass, second is standard unit for measuring time
5 0
3 years ago
Read 2 more answers
A torque of 36.5 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result
vivado [14]

Answer:

21.6\ \text{kg m}^2

3.672\ \text{Nm}

54.66\ \text{revolutions}

Explanation:

\tau = Torque = 36.5 Nm

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 10.3 rad/s

t = Time = 6.1 s

I = Moment of inertia

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_1 t\\\Rightarrow \alpha_1=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha_1=\dfrac{10.3-0}{6.1}\\\Rightarrow \alpha_1=1.69\ \text{rad/s}^2

Torque is given by

\tau=I\alpha_1\\\Rightarrow I=\dfrac{\tau}{\alpha_1}\\\Rightarrow I=\dfrac{36.5}{1.69}\\\Rightarrow I=21.6\ \text{kg m}^2

The wheel's moment of inertia is 21.6\ \text{kg m}^2

t = 60.6 s

\omega_i = 10.3 rad/s

\omega_f = 0

\alpha_2=\dfrac{0-10.3}{60.6}\\\Rightarrow \alpha_1=-0.17\ \text{rad/s}^2

Frictional torque is given by

\tau_f=I\alpha_2\\\Rightarrow \tau_f=21.6\times -0.17\\\Rightarrow \tau=-3.672\ \text{Nm}

The magnitude of the torque caused by friction is 3.672\ \text{Nm}

Speeding up

\theta_1=0\times t+\dfrac{1}{2}\times 1.69\times 6.1^2\\\Rightarrow \theta_1=31.44\ \text{rad}

Slowing down

\theta_2=10.3\times 60.6+\dfrac{1}{2}\times (-0.17)\times 60.6^2\\\Rightarrow \theta_2=312.03\ \text{rad}

Total number of revolutions

\theta=\theta_1+\theta_2\\\Rightarrow \theta=31.44+312.03=343.47\ \text{rad}

\dfrac{343.47}{2\pi}=54.66\ \text{revolutions}

The total number of revolutions the wheel goes through is 54.66\ \text{revolutions}.

3 0
3 years ago
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