First, we need to find the acceleration
F = ma
9850 N = (815 kg + 61 kg)a
a = 11.24
the read of the scale during the acceleration is :
mg + ma
= (61 kg x 9.8) + (61 kg x 11.24)
= 1283.4 N
hope this helps
Answer:
A) 
Explanation:
Since a = g - bv,
We can substitute a = dv/dt into the equation.
Then, the equation will be like dv/dt = g - bv.
So we got first order differential equation.
As known, v = 0 at t = 0, and v = g/b at t = ∞.
Since 
⇒ 
So take the integral of both side.
Since for t=0, v = 0 ⇒ 
Answer: 4.27 *10^6 N/C
Explanation: In order to calculate the electric field along the axis of charged ring we have to use the following expression:
E=k*x/(a^2+x^2)^3/2 where a is the ring radius and x the distance to the point measured from the center of the ring.
Replacing the data we have:
E= (9* 10^9* 0.3* 50 * 10^-6)/(0.1^2+0.3^2)^3/2
then
E=4.27 * 10^6 N/C
Answer:F(of gravity) = MA
F(normal force) = MA * cos(angle)
F = 72 * 9.81 * cos28
Don't have a calculator, so can't really do all the math right there. So just plug that in
Explanation:
i dont really know
