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Romashka [77]
3 years ago
12

In which one of the following situations does a car have a WESTWARD acceleration? The car travels westward and slows down. The c

ar travels westward at constant speed. The car travels eastward and speeds up. The car travels eastward and slows down. The car starts from rest and moves toward the east.
Physics
1 answer:
DENIUS [597]3 years ago
4 0

Explanation:

Let east direction is negative and west direction is positive. The acceleration of an object is given by :

a=\dfrac{v-u}{t}

Where

v is the final speed

u is the initial speed

t is the time taken

As the car decelerates, the final speed of the car is less as compared to the initial speed. As a result, its acceleration is negative. It means the car travels eastward and slows down. Hence, this is the required solution.

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The center of mass of a 0.30-kg (non-uniform) meter stick is located at its 45-cm mark. What is the magnitude of the torque (in
lbvjy [14]

Answer:

The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

Explanation:

Given that,

Mass of the meter stick, m = 0.3 kg

Center of mass is located at its 45 cm mark.

We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :

\tau=r\times F\\\\\tau=(45-28)\times 10^{-2}\times 0.3\times 9.79\\\\\tau=0.499\ N-m

or

\tau=0.5\ N-m

So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

6 0
4 years ago
The gravity tractor, is a proposed spacecraft that will fly close to an asteroid whose trajectory threatens to impact the Earth.
Crazy boy [7]

Answer:

F_g=461lb_f

Explanation:

First calculate the mass of the asteroid. To do so, you need to find the volume and know the density of iron.

If r = d/2 = 645ft, then:

V = \frac{4}{3} \pi r^3

V = \frac{4}{3} \pi r^3\\V = 1.124\times10^{9}ft^3\delta_{iron}=m/V=491lb/ft^3m=V\times\delta=5.519\times10^{11}lb

In order to find force, use Newton's universal law of gravitation:

F_g=G\frac{m_1m_2}{d^2}

Where,

G= the gravitational constant:

G= 1.068846 \times10^{-9} ft^3 lb^{-1} s^{-2}

F_g=461lb_f

4 0
3 years ago
Taking the density of air to be 1.29 kg/m3, what is the magnitude of the angular momentum (in kg · m2/s) of a cubic meter of air
Svet_ta [14]

The magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

The rotating equivalent of linear momentum in physics is called angular momentum. Because it is a conserved quantity—the total angular momentum of a closed system stays constant—it is significant in physics. Both the direction and the amplitude of angular momentum are preserved.

Given the density of air to be 1.29 kg/m3 and a wind speed of 73.0 mi/h

We have to find the magnitude of the angular momentum

Let,

ρ = Density of air = 1.29 kg/m^3

v = Speed of wind = 73.0 mi/h = 0.032 km/s

M = angular momentum of air

Let the volume of air be 1 m^3

Mass = Volume x ρ = 1 x 1.29 = 1.29 kg

Momentum = M = mass x velocity

Momentum = 1.29 x 0.0032

Momentum = 4.128 x 10^(-3) kg·m^2/s

Hence the magnitude of the angular momentum of air will be 4.128 x 10^(-3) kg·m^2/s

Learn more about angular momentum here:

brainly.com/question/7538238

#SPJ10

8 0
2 years ago
What is stomato and write its functions ​
Nataly_w [17]

Answer:

Stomata- In botany, a stoma (also stomate; plural stomata) is a tiny opening or pore that is used for gas exchange. They are mostly found on the under-surface of plant leaves. Its functions are- The gas exchange that occurs when stomata are open facilitates photosynthesis. Mark Brainliest Pls

Explanation:

8 0
4 years ago
PLZZZZZZZZZ HELPPPPP. BRAINLEST GIVEN What is a force of attraction between an object and the earth due to gravity?
kotykmax [81]

Answer:

acceleration due to gravity: -9.8 m/s^2

Fg=mass of object*(-9.8)

Explanation:

This is a pretty vague question, but I'll answer as best I can.

All matter has gravity. YOU have gravity, although your gravitational pull is small. So, the force of attraction between the Earth and an object on Earth is modeled as

Force of gravity=(Gravitational constant*mass of object 1*mass of object  2)/distance between objects squared

Note that distance between an object on Earth and Earth is the radius of Earth (distance to Earth's core/center of mass)

6 0
3 years ago
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