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MariettaO [177]

3 years ago

14

When limestone rock, which is principally calcium carbonate, is heated, a reaction occurs. If 11.7 g of carbon dioxide were prod

uced in the lab from the decomposition of 30.7g of calcium carbonate, what is the percent yield for the reaction?

1 answer:

aev [14]3 years ago

6 0

Answer: 86.7 %

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

a) moles of $CaCO_3$

$\text{Number of moles}=\frac{30.7g}{100g/mol}=0.307moles$

$CaCO_3\rightarrow CaO+CO_2$

According to stoichiometry :

1 moles of $CaCO_3$ give = 1 mole of $CO_2$

Thus 0.307 moles $CaCO_3$ give = $\frac{1}{1}\times 0.307=0.307moles$ of $CO_2$

Mass of $CO_2=moles\times {\text {Molar mass}}=0.307moles\times 44g/mol=13.5g$

$\%\text{ yield }=\frac{\text{Actual yield}}{\text{Theoretical yield }}\times 100=\frac{11.7g}{13.5g}\times 100=86.7\%$

Therefore, the percent yield for the reaction is, 86.7%

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Answer : The answer is, $0.2\times 10^{-4}$

Explanation :

Scientific notation : It is defined as the way or representation of expressing the number that are too big or too small that is written in the decimal form. That means always written in the power of 10 form.

For example : 8000 is written as, $8.0\times 10^3$ in this notation, the significant figure is, 1 but $0.8\times 10^4$ in this notation, the significant figures are, 2

The given problem are :

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6 0

3 years ago

Read 2 more answers

Why can a liquid change to take the shape of its container but NOT expand to fill the container itself?

tiny-mole [99]

Answer: Option (C) is the correct answer.

Explanation:

Molecules in a liquid have less force of attraction as compared to solids. But liquid molecules have more force of attraction as compared to gases.

Since molecules of a gas are held together by weak Vander waal forces, therefore, they expand to fill the container whereas molecules in a liquid are not expanded in a container like gases because of more force of attraction within molecules of liquids as compared to gases.

Hence, a liquid can take the shape of container in which it is kept.

Thus, we can conclude that out of the given options, a liquid change to take the shape of its container but NOT expand to fill the container itself because the particles of a liquid are held together loosely enough to flow, but not so loose that they expand.

4 0

4 years ago

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calculate the difference in slope of the chemical potential against temperature on either side of the normal freezing point of w

kipiarov [429]

Answer:

(a) The normal freezing point of water (J·K−1·mol−1) is $-22Jmole^-^1k^-^1$

(b) The normal boiling point of water (J·K−1·mol−1) is $-109Jmole^-^1K^-^1$

(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole

Explanation:

Lets calculate

(a) - General equation -

$(\frac{d\mu(\beta )}{dt})p-(\frac{d\mu(\alpha) }{dt})_p$ = $-5_m(\beta )+5_m(\alpha )$ = $-\frac{\Delta H}{T}$

$\alpha ,\beta$ → phases

ΔH → enthalpy of transition

T → temperature transition

$(\frac{d\mu(l)}{dT})_p -(\frac{d\mu(s)}{dT})_p$ = $= -\frac{\Delta_fH}{T_f}$

= $\frac{-6.008kJ/mole}{273.15K}$ ( $\Delta_fH$ is the enthalpy of fusion of water)

= $-22Jmole^-^1k^-^1$

(b) $(\frac{d\mu(g)}{dT})_p-(\frac{d\mu(l)}{dT})_p= -\frac{\Delta_v_a_p_o_u_rH}{T_v_a_p_o_u_r}$

= $\frac{40.656kJ/mole}{373.15K}$ ( $\Delta_v_a_p_o_u_rH$ is the enthalpy of vaporization)

= $-109Jmole^-^1K^-^1$

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$[\mu(l-5$ ° $C)-\mu(l,0$ ° $C)]$ = $[\mu(s-5$ ° $C)-\mu(s,0$ ° $C)]$ $=-S_m$ ΔT

$\mu(l,-5$ ° $C)-\mu(s,-5$ ° $C)=-Sm\DeltaT [\mu(l,0$

$\Delta\mu=(21.995Jmole^-^1K^-^1)\times (-5K)$

= 109J/mole

6 0

3 years ago

Valence Bond theory predicts that tin will use what hybrid orbitals in Snf5 -1

LUCKY_DIMON [66]

Answer:

sp3d

Explanation:

The ground state electronic configuration of tin is written as; [Kr] 5s²4d¹⁰5p². Hybridization is a concept used to explain the combination of orbitals of appropriate energy to produce suitable orbitals that could be used for bonding.

In forming the compound Snf5^ -1, we have to hybridize the following orbitals on tin; 5p, 5d and 6s orbitals. This gives us a set of sp3d hybrid hence the answer.

6 0

3 years ago