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Soloha48 [4]
3 years ago
11

Monosodium glutamate (MSG), a flavor enhancer, has been blamed for "Chinese restaurant syndrome," the symptoms of which are head

aches and chest pains. MSG has the following composition by mass: 35.51 percent C, 4.77 percent H, 37.85 percent O, 8.29 percent N, and 13.60 percent Na. What is its molecular formula if its molar mass is about 169 g?
Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
3 0

Answer:

The molecular formula of mono sodium glutamate is C_5H_8O_4N_1Na_1

Explanation:

Molar mass of sodium glutamate,M = 169 g/mol

let the molecular formula be C_aH_bO_cN_dNa_e

Percentage of carbon in the M.S.G. =35.52 %

35.51\%=\frac{a\times 12 g/mol}{169 g/mol}

a = 5

Percentage of Hydrogen in the M.S.G. = 4.77 %

4.77\%=\frac{b\times 1 g/mol}{169 g/mol}

b = 8

Percentage of oxygen in the M.S.G. =37.85 %

8.29\%=\frac{c\times 16 g/mol}{169 g/mol}

c = 3.99 ≈ 4

Percentage of nitrogen in the M.S.G. = 8.29 %

4.77\%=\frac{d\times 14 g/mol}{169 g/mol}

d = 1

Percentage of sodium in the M.S.G. =13.60 %

13.60\%=\frac{c\times 23g/mol}{169 g/mol}

e = 0.99 ≈ 1

The molecular formula be :C_aH_bO_cN_dNa_e=C_5H_8O_4N_1Na_1

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sukhopar [10]

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Explanation:

A procedure called mixture melting point would be used to determine whether or not the suspected compound is identical to the unknown.

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4 0
3 years ago
For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of
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The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

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Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe  = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O;  Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

 


7 0
3 years ago
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The half life of radium-226 is 1600 years. If you have 200 grams of radium today how many grams would be present in 8000 years?
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Answer:

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Explanation:

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