Selective breeding
The Alleles
DNA
X and Y chromosome from mother and father
Nucleus
Gene
<u>Explanation:</u>
- In selective breeding, a specific trait of the animal is considered and the gene coding for that trait is used to create new breeds. Example - cow producing lot of milk.
- Genotypes are always expressed by the alleles.
- Example - Genotype of Tall plants would be TT or Tt
- Information is passed from parents to offsprings from the information stored in DNA.
- A gender of an individual is determined by the x chromosomes of mother and X and Y chromosome of father.
- X chromosome from mother and X chromosome from father would form a female and X chromosome from mother and Y chromosome from father would form a male.
- DNA is located inside the nucleus of the cell
- Gene is the segment of chromosome that codes for a specific protein. The non coding segment of chromososme is heterochromatin.
Answer:
6896
Explanation:
when you covert you use decimals
Answer:
188.5g of dextrose are needed
Explanation:
In Weight per volume percentage - %(w/v) -, the concentration is defined as the mass of solute in grams -In this case, dextrose-, in 100mL of solution.
As you want to prepare 725mL of a 26.0% (w/v) solution. you need:
725mL * (26g / 100mL) = 188.5g of solute =
<h3>188.5g of dextrose are needed</h3>
Answer:
1. Absorbs electromagnetic energy
2. Energy difference between the two orbits.
Explanation:
Bohr precisely describe the processes of absorption and emission of energy in terms of electronic structure. According to Bohr's model, an electron would absorb energy in the form of photons to get excited to a higher energy level as long as the photon's energy was equal to the energy difference between the initial and final energy levels. After jumping to the higher energy level or the excited state, the excited electron would be in a less stable position, so it would quickly emit a photon to relax back to a lower, more stable energy level.
The molar mass of a, b and c at STP is calculated as below
At STP T is always= 273 Kelvin and ,P= 1.0 atm
by use of ideal gas equation that is PV =nRT
n(number of moles) = mass/molar mass therefore replace n in the ideal gas equation
that is Pv = (mass/molar mass)RT
multiply both side by molar mass and then divide by Pv to make molar mass the subject of the formula
that is molar mass = (mass x RT)/ PV
density is always = mass/volume
therefore by replacing mass/volume in the equation by density the equation
molar mass=( density xRT)/P where R = 0.082 L.atm/mol.K
the molar mass for a
= (1.25 g/l x0.082 L.atm/mol.k x273k)/1.0atm = 28g/mol
the molar mass of b
=(2.86g/l x0.082L.atm/mol.k x273 k) /1.0 atm = 64 g/mol
the molar mass of c
=0.714g/l x0.082 L.atm/mol.K x273 K) 1.0atm= 16 g/mol
therefore the
gas a is nitrogen N2 since 14 x2= 28 g/mol
gas b =SO2 since 32 +(16x2)= 64g/mol
gas c = methaneCH4 since 12+(1x4) = 16 g/mol
