A rocket travels 4500 meters in 150 seconds. What is its average speed?

Chemistry

1 answer:

Dmitrij [34]2 years ago

5 0

Answer:

Your average speed was 3.77 Miles per hour

Explanation:

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If a certain compound has a formula XCl₃ what is the valency of X?

asambeis [7]

The general form of a compound can be written in the form of:

[X(a) Y(b)] ^ c

Where a and b are subscripts, and c is the superscript of the whole formula.

The relationship that we can derived here between the constants is:

(valence of X) * a + (valence of Y) * b = c

Since the formula obviously has no superscript, therefore c = 0. We also know in chemistry class that the valence of Cl is -1, therefore:

valence of X * 1 + (-1) * 3 = 0

valence of X - 3 = 0

<span>valence of X = 3</span>

6 0

3 years ago

Some commercially available algaecides for swimming pools claim to contain 7% copper. Could the method used in this experiment t

AleksandrR [38]

Answer:

Explanation:

7% copper implies 7 w/v%(weight/volume %) of copper. This implies a 100 mL algaecide arrangement contains 7 grams of copper.
Henceforth we have a thought of the measure of copper that ought to be available in a given example of algaecide.
Indeed, even a 1 mL algaecide test is sufficient to discover the percentage of copper in it.
so a 25mL sample of algaecide must have around 1.75g of copper.

4 0

3 years ago

The molarity of a sodium hydroxide (NaOH) solution is 0.2 M. The molar mass of NaOH is 40 g/mol. If the solution contains 20 g o

mote1985 [20]

Answer:

$\large \boxed{\text{2.5 L}}$

Explanation:

1. Calculate the moles of NaOH.

$\text{Moles} = \text{20 g} \times \dfrac{\text{1 mol}}{\text{40 g}} = \text{0.50 mol}$

2. Calculate the volume of NaOH

$\begin{array}{rcl}\\\text{Molar concentration} &= &\dfrac{\text{moles}}{\text{litres}}\\\\ n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.2 mol}}{\text{1 L}} &=& \dfrac{\text{0.50 mol}}{V}\\\\ \dfrac{0.2V}{\text{1 L}} & = & 0.50\\\\0.2V &= & \text{0.50 L}\\V & = & \dfrac{\text{0.50 L}}{0.2}\\\\& = & \textbf{2.5 L}\\\end{array}\\\text{The volume of the solution is $\large \boxed{\textbf{2.5 L}}$}$