C would be the only logical answer if you really think about what it’s saying about the instrument.
Answer:
The strength of an individual H bond depends on the polarity of the H-X bond and therefore on the electronegativity of X ( the more delta positive the H atom, the stronger the electrostatic force of attraction between it and a lone pair of electrons). Thus, on a per bond basis, HF H bonding is strongest. However, as water has two H atoms, each molecule can form two H bonds so on a per molecule basis, water H bonding is strongest (this is evidenced by the boiling points of the three substances; NH3 < HF < H2O.)
Explanation:
Correct me if I'm wrong
The answer for your question is <span>No. This is because in given conditions, it is not the most stable form of oxygen's element. It will not equate into zero because there will be charge remained after balancing the equation.
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