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ioda
3 years ago
13

Na3AsO4 is a salt of a weak base that can accept more than one proton. If 18.4 g of Na3AsO4 is dissolved in water to make 250mL

of solutions how many moles of sodium cations are in the solution?
Answer in units of mol.
Chemistry
1 answer:
harina [27]3 years ago
4 0

Answer:

0.266 moles of Na⁺

Explanation:

First step we dissociate the salt:

Na₃AsO₄  →  3Na⁺  +  AsO₄⁻³

From 1 mol of sodium arsenate, we must have 3 moles of sodium cation and 1 mol of arsenate.

We determine the moles of salt:

18.4 g . 1 mol/ 207.89 g = 0.0885 moles of salt.

We apply the followring rule of three:

1 mol of salt has 3 moles of Na⁺

0.0885 moles of salt may have (0.0885 . 3) / 1 = 0.266 moles of Na⁺

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A postulate is a statement recognized as a truth. The kinetic molecular theory has five postulates. Which of the following is NO
MrMuchimi

Answer:

2nd option is NOT a postulate of kinetic theory of gases

Explanation:

actually particles move in straight random motion and create bombardment with the molecules and container

3 0
3 years ago
the diagram shows light striking a pane of glass . some of the light is reflected , and some of the light is transmitted. the le
GrogVix [38]
When light crosses any barrier 
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3 years ago
Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe
jeyben [28]

Answer:

0.55 atm

Explanation:

First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by

n=\frac{m}{M_m}

where

m = 1.00 g is the mass of the gas

Mm = 44.0 g/mol is the molar mass of the gas

Substituting,

n=\frac{1.00 g}{44.0 g/mol}=0.0227 mol

Now we can find the pressure of the gas by using the ideal gas law:

pV=nRT

where

p is the gas pressure

V = 1.00 L is the volume

n = 0.0227 mol is the number of moles

R = 0.082 L/(atm K mol) is the gas constant

T = 25.0 C + 273 = 298 K is the temperature of the gas

Solving the formula for p, we find

p=\frac{nRT}{V}=\frac{(0.0227 mol)(0.082 L/(atm K mol))(298 K)}{1.00 L}=0.55 atm

8 0
4 years ago
SeF6 1. Lewis Structure 2. Perspective drawing 3. Number of atoms bonded to central atom 4. Number of non-bonding electron pairs
Anarel [89]

The answer is- SF_{6} is octahedral in electronic and molecular geometry with 6 Fluorine atoms bonded to central atom S.

Lewis structures are the diagrams in which the valence electrons of the atoms of a compound are arranged around the atoms showing the bonding between the atom and the lone pair of electrons existing in the molecule.

Determine the molecular geometry of SF_{6}.

  • Valence Shell Electron Pair Repulsion theory is commonly known as VSEPR theory and it helps to predict the geometry of molecules.
  • According to this theory, electrons are arranged around the central atom of the molecule in such a way that there is minimum electrostatic repulsion between these electrons.
  • Now, calculate the total number of valence electrons in SF_{6}.

Valence\ electrons\ in\ SF_{6}= Valence\ electrons\ in\ S +\ 6(Valence\ electrons\ in\ F)

Valence electrons of S = 6

Valence electrons of F = 7

Thus, the valence electrons in SF_{6} are-

Valence\ number\ of\ electrons\ in\ SF_{6} = (6) + 6(7) = 48\ electrons.

  • The Lewis structure of SF_{6} is - (Image attached).
  • In the structure, the number of atoms bonded to central atom (S) = 6.
  • Number of non-bonding electron pairs on the central atom = 0 (as all the valence electrons are bonded to F).
  • Electronic geometry in case of 6 bond pairs is octahedral.
  • Molecular geometry us also octahedral with bond angles 90°.
  • Central atom is sp3d2 hybridised.
  • SF_{6} is a non-polar molecule.

To learn more about Lewis structures visit:

brainly.com/question/12307841?referrer=searchResults

#SPJ4

7 0
1 year ago
When the valves are opened and the gases are allowed to mix at a constant temperature, what is the distribution of atoms in each
jek_recluse [69]

Answer:

Equal number of atoms of each gas in each container

Explanation:

When the valves opened, the two contaienrs become one and the gases beging to mix by diffusion. This phenomenom is produced by the differeces of concentration of a gas between two points of the container.

The gases will continue diffunding util their concentration in both containers are equal.

7 0
3 years ago
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