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Slav-nsk [51]
3 years ago
8

Design a synthesis of acetophenone from benzene or toluene. 1275q Part 1 out of 5 Choose the best option for the nucleophile pre

cursor to acetophenone. 1275p1
Chemistry
1 answer:
Trava [24]3 years ago
5 0

Answer:

A Fridiel craft catalyst will convert benzene to acetophenone.

Permanganate catalyst can be used to convert toluene to acetophenone.

Explanation:

Benzene can be reduced to acetophenone by the addition of anhydrous aluminium chloride, AlCl₃

The mechanism is as follows:

Benzene + Acetyl choloride → acetophenone

To convert toluene to acetophenone, the following steps are necessary:

  • Oxidation of Toluene to Benzoic acid.

     This is done by refluxing toluene with alkaline potassium permanganate         (KMnO₄+ Na₂CO₃).

  • Benzoic acid is converted to Benzoyl chloride by treating with thioyl chloride and heating at about 80 ⁰C.
  • Benzoyl chloride is treated with methyl lithium to form Acetophenone.
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Defective collagen proteins affect an individuals joints, as <u>collagen is an important component protein in body</u><u> connective tissues</u>

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Provide a balanced molecular equation, total ionic, and net ionic equation for sodium phosphate and zinc acetate.
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Answer: Balanced molecular equation :

2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)

Total ionic equation:

6Na^+(aq)+3PO_4^{2-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)  

The net ionic equation:

2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)

Explanation:

Complete ionic equation : In complete ionic equation, all the substances that are strong electrolyte are present in an aqueous state as ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

When sodium phosphate and zinc acetate then it gives zinc phosphate and sodium acetate as  product.

The balanced molecular equation will be,

2Na_3PO_4(aq)+3(CH_3COO)_2Zn(aq)\rightarrow 6CH_3COONa(aq)+Zn_3(PO_4)_2(s)

The total ionic equation in separated aqueous solution will be,

6Na^+(aq)+2PO_4^{3-}(aq)+6CH_3COO^-(aq)+3Zn^{2+}(aq)\rightarrow 6CH_3COO^-(aq)+6Na^+(aq)+Zn_3(PO_4)_2(s)

In this equation, and  are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

2PO_4^{3-}(aq)+3Zn^{2+}(aq)\rightarrow Zn_3(PO_4)_2(s)

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