1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reika [66]
3 years ago
7

Type in the box below the balanced, chemical equation that describes the complete combustion reaction of starch (C18H30O15). To

receive full credit, you must include the phases of all the reactants and products as well. Hints: you should know the two products. Note that the compound being combusted contains oxygen.
Chemistry
2 answers:
nignag [31]3 years ago
7 0

Answer: C18H30O15 (solid)  + 9 O2 (Gas) --> 18 CO2 (Gas) + 15 H20 (Liquid)

Explanation:

So we know that the products of combustion are water vapor and carbon dioxide so we can put those there under the products. Also it needs to react with fire so the other reaction is gonna be oxygen gas. So if we balance out the equations by multiplying the Carbon Dioxide to reach the necessary amount of Carbon, and water so that we can reach the required amount of Hydrogen, all we would need to do is add oxygen to the left side which we already have a molecule for that.

Snowcat [4.5K]3 years ago
4 0

Answer:

C18H30O15(s) + 18O2(g) → 18CO2(g) + 15H2O(l)

Explanation:

Step 1: Data given

The reactants are C18H30O15 and O2

The products of a combustion reaction are CO2 and H2O

Step 2: The unbalanced equation

C18H30O15(s) + O2(g) → CO2(g) + H2O(l)

Step 3: Balancing the equation

C18H30O15(s) + O2(g) → CO2(g) + H2O(l)

On the left side we have 18x C, on the right side we have 1x C (in CO2). To balance the amount of C on both sides, we have to multiply CO2 on the right side by 18

C18H30O15(s) + O2(g) → 18CO2(g) + H2O(l)

On the left side we have 30X H, on the right side we have 2x H (in H2O). To  balance the amount of H on both sides, we have to multiply H2O on the right side by 15.

C18H30O15(s) + O2(g) → 18CO2(g) + 15H2O(l)

On the left side we have 17X O, on the right side we have 51x O (36x in CO2 and 15x in H2O). To  balance the amount of O on both sides, we have to multiply O2 on the left side by 18. Now the equation is balanced.

C18H30O15(s) + 18O2(g) → 18CO2(g) + 15H2O(l)

You might be interested in
Which of the following categories of small bodies in the solar system does Ceres belong to?
Natalija [7]
Ceres is a dwarf planet, so A.
4 0
3 years ago
A temperature of 50°F is equal to °C.
Tema [17]
50 degrees Fahrenheit is equal to about 10 degrees Celsius. Hope this helps!
6 0
3 years ago
Read 2 more answers
Calculate the energy required to melt 21 g of ice at 0 oC.
vladimir1956 [14]

<u>We are given:</u>

Mass of ice = 21 grams

The ice is already at 0°c, the temperature at which it melts to form water

Molar heat of fusion of Ice = 6.02 kJ/mol

<u>Finding the energy required:</u>

<u>Number of moles of Ice: </u>

Molar mass of water = 18 g/mol

Number of moles = given mass/ molar mass

Number of moles = 21 / 18 = 7/6 moles

<u>Energy required to melt the given amount of ice:</u>

Energy = number of moles * molar heat of fusion

Energy = (7/6) * (6.02)

Energy = 7.02 kJ OR 7020 joules

7 0
3 years ago
We might think of a porous material as being a composite wherein one of the phases is a pore phase. Estimate upper and lower lim
eduard

Answer:

The upper and lower limits for the room-temperature thermal conductivity of a magnesium oxide material having a volume fraction of 0.10 of pores that are filled with still air are

Ku = 38.252 W/mK

K lower = 0.199 W/mK

Explanation:

As we know  

Ku = Vp * Kair + Vmagnesium * K metal  

Ku = 0.10 *0.02 + (1-0.25) * 51

Ku = 38.252 W/mK

The lower limit  

K lower = Kmetal* Kair/( Vp * Kmetal + Vmetal * K air)

K lower = (0.02*51)/(0.10*51 + 0.90 * 0.02)

K lower = 0.199 W/mK

8 0
2 years ago
Pre-Lab Study Questions / 9
jok3333 [9.3K]

Answer:

See detailed answer with explanation below.

Explanation:

Valence electrons are electrons found on the outermost shell of an atom. They are the electrons in an atom that participate in chemical combination. Recall that the outermost shell of an atom is also referred to as its valence shell. Let us consider an example; if we look at the atom, sodium-11, its electronic configuration is 2,8,1. The last one electron is the valence electron of sodium which is found in its outermost or valence shell.

Positive ions are formed when electrons are lost from the valence shell of an atom. For instance, if the outermost electron in sodium is lost, we now form the sodium ion Na^+ which is a positive ion. Positive ions possess less number of electrons compared to their corresponding atoms.

Negative ions are formed when one or more electrons is added to the valence shell of an atom. A negative ion possesses more electrons than its corresponding atom. For example, chlorine(Cl) contains 17 electrons but the chloride ion (Cl^-) contains 18 electrons.

In molecular compounds, a bond is formed when two electrons are shared between the bonding atoms. Each bonding atom may contribute one of the shared electrons (ordinary covalent bond) or one of the bonding atoms may provide the both shared electrons (coordinate covalent bond). The shared pair may be located at an equidistant position to the nucleus of both atoms. Similarly, the electron may be drawn closer to the nucleus of one atom than the other (polar covalent bond) depending on the electro negativity of the two bonding atoms.

The electrons are shared in order to complete the octet of each atom by so doing, the both bonding atoms now obey the octet rule. For example, two chlorine atoms may come together to form a covalent bond in which each chlorine atom has an octet of electrons on its outermost shell.

4 0
3 years ago
Other questions:
  • What color is the 2,6-dichloroindophenol solution in acidic solutions?
    9·1 answer
  • What noise does hydrogen gas make when ignited
    8·2 answers
  • Help me out please this is my last attempt on the quiz
    8·2 answers
  • Calculate ΔH (in kJ) for the process Hg2Br2(s) → 2 Hg(l) + Br2(l) from the following information.
    13·2 answers
  • A person who has a mass of 60kg run up a flight of stairs 12m high in 20 seconds What is the weight of the person​
    7·1 answer
  • Please anyone help please I will pray for you
    15·1 answer
  • A student wants to know how many grams of water are made from 5.00g of oxygen gas. Which step goes in the spot with the
    6·1 answer
  • 29.) What charge would you expect from a Group 1 atom when it becomes an ion?
    5·2 answers
  • If I use the answers from here wouldn't that come up as a high % plagiarism ??
    15·2 answers
  • Describe how intermolecular forces affect solvation.
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!