Hey! so I can help you with the beginning!
1. The ratio of Fe to O2 is 4:3 so since they tell you that you have 56 moles of Fe, all you have to do is plug in the information. So 56/4 = 14 and 3 x 14 = 42. To conclude, the answer for number one is 42 moles of O2.
2.Same thing from #1 except the ratio is 4:2 (since we are now talking about Fe2O3) so you divide 56/4 and get 14 so you multipy 2x 14 which gives you 28. To conclude, the answr to numbner 2 is 28 moles of Fe2O3.
3. On this question it is asking for grams, not moles, so we have to look on our periodic table and look for the atomic mass of Fe. To start off the problem you are going to have to find the amount of moles of Fe needed to react with 27 moles of O2 so the ratio will be 4:3 so you need to divide 27/3 which gives you 9. Multiply 9x4 and that gives you 36 moles. DONT FORGET TO CONVERT TO GRAMS. The final answer will be 2,010.42 g of Fe after you multiply 36 x 55.845 g (Fe atomic weight.
I would help you more but I have school tomorrow as well... I help this helped though.
