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ratelena [41]
4 years ago
14

A person walks first at a constant speed of 5.50 m/s along a straight line from point A to point B and then back along the line

from B to A at a constant speed of 3. What is her average speed over the entire trip (in m/s) ?
Physics
1 answer:
Sav [38]4 years ago
8 0

Answer:

4.25 m/s

Explanation:

They walked the first distance at 5.50 m/s, then the same distance at 3 m/s.

Since the distances are equal, the average speed is simply the average of 5.50 and 3.

(5.50 + 3) / 2 = 4.25

Her average speed over the entire trip is 4.25 m/s.

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A positively charged objectwith a mass of 0.114 kg oscillates at the end of a spring, generating ELF (extremely low frequency) r
katen-ka-za [31]

Answer:

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        Solving for f, we get the frequency of the radio waves:

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  • Now, from the Hooke's law, we know that the mass attached at the end of the spring oscillates with an angular frequency defined by  a fixed relationship between the spring constant k and the mass m, as follows:

       \omega_{o}^{2} =\frac{k}{m}  (1)

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  • We also know that f in (2) is the same that we got for the radio waves, so replacing (2) in (1), and rearranging terms, we can solve for k, as follows:
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3 0
3 years ago
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