Answer:
V₂ = 14.07 L
Explanation:
As this gas is cooled at constant temperature of 320 K, this means that we are on an isothermal process, and according to the 1st law of thermodynamics:
Q = W (1)
And as the temperature is constant, we can use the following expression to calculate the Work done:
W = nRT ln(V₁/V₂) (2)
However, as Q = W, we can replace heat into the above expression and then solve for V₂:
Q = nRT ln(V₁/V₂)
Replacing we have:
1200 = (1.5 * 8.314 * 320) ln(19/V₂)
1200 = 39907.2 ln(19/V₂)
ln(19/V₂) = 1200/3990.72
ln(19/V₂) = 0.3007
19/V₂ = e^(0.3007)
V₂ = 19 / e^(0.3007)
<h2>
V₂ = 14.07 L</h2>
Hope this helps
The total momentum before and after the collision must be conserved.
The total momentum before the collision is:

where m1 and m2 are the masses of the two players, and

and

their initial velocities. Both are considered with positive sign, because the two players are running toward the same direction.
The final momentum is instead

because now the two players are moving together with a total mass of (m1+m2) and final speed vf.
By requiring that the momentum is conserved

we can calculate vf, the post-collision speed:


and the direction is the same as the direction of the players before the collision.
Answer:
B. Direction
Explanation:
Speed is a scalar quantity and doesn't keep track of direction : Velocity is a vector quantity and is direction aware.
Answer:
The system's potential energy is -147 J.
Explanation:
Given that,
Energy = 147 J
We know that,
System is isolated and it is free from external forces.
So, the work done by the external forces on the system should be equal to zero.

We need to calculate the system's potential energy
Using thermodynamics first equation

Put the value into the formula


Hence, The system's potential energy is -147 J.
Answer:
C-less than
Explanation:
Distance is total distance traveled (1000m here if you stop where you started).
Displacement is your final distance from where you started (0m if you stop where you started).
0m<1000m