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Greeley [361]
3 years ago
11

Which statement best describes gravity

Physics
1 answer:
jekas [21]3 years ago
5 0

Answer:

D

Explanation:

it is the force that acts between any two objects in the universe

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When is a body said to be motion (movement )?
Stels [109]

A body is said to be in motion when it's position changes continuously.

3 0
3 years ago
Which energy changes take place when a pedaling cyclist uses a generator (dynamo) to light his bicycle
Fynjy0 [20]

When the pedaling cyclist uses a generator (dynamo) to light his bicycle lamp, the energy change is from mechanical to electrical.

<h3>Law of conservation of energy</h3>

The law of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.

Thus, we can conclude the following as it relates to energy changes;

  • When the pedaling cyclist uses a generator (dynamo) to light his bicycle lamp, the energy change is from mechanical to electrical.

Learn more about conservation of energy here: brainly.com/question/166559

4 0
2 years ago
Read 2 more answers
A certain fm radio station broadcasts electromagnetic waves at a frequency of 125000 hertz. these radio waves travel at a speed
faltersainse [42]
Speed = frequency x wavelength
300,000,000 = 125000 x wavelength
wavelength = 125000/300,000,000 =4.16667x10^-4 meters
or 4.1667E-4 meters
4 0
3 years ago
An object traveling at constant speed v in a circle of radius R has an acceleration am 5 m/s2. If both R and v are doubled, what
MakcuM [25]

Answer:

im pretty sure its 10 m/s but its kinda hard sorry

Explanation:

7 0
3 years ago
Will mark as BRAINLIEST....... The Displacement x of particle moving in one dimension under the action of constant force is rela
pentagon [3]

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

x=4t^3+3t^2-5t+2

Where,

x is in meters and t is in sec

We know that,

Velocity,

v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5

(a) i. t = 2 s

v=12(2)^2+6(2)-5=55\ m/s

At t = 4 s

v=12(4)^2+6(4)-5=211\ m/s

(b) Acceleration,

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6

Pu t = 3 s in the above equation

So,

a=24(3)+6\\\\a=78\ m/s^2

Hence, this is the required solution.

3 0
3 years ago
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