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3 years ago

Which factors are used to calculate the kinetic energy of an object? Check all that apply. gravity velocity volume mass height

Physics

2 answers:

Sonja [21]3 years ago

8 0

Quantities that determine the kinetic energy of a body are its mass and velocity

Answer: mass and velocity

Explanation:

The kinetic energy of a body is the energy possessed by an object by virtue of its motion. It is given by the equation

$k= \frac{1}{2}mv^2$

Where m represents mass of the body and v represents its velocity.

Two bodies of equal velocity but different mass the heavier body will have greater kinetic energy. When an object is at rest its velocity is equal to zero. Thus its kinetic energy will be zero. Hence it can be concluded that only moving bodies have kinetic energy.

Stationary objects placed at a height possess potential energy which is the energy by virtue of their position or configuration. The total mechanical energy of a system is the sum of potential and kinetic energy.

maksim [4K]3 years ago

8 0

Answer:

mass, velocity

Explanation:

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Suppose you are at the center of a large freely-rotating horizontal turntable in a carnival funhouse. As you crawl toward the ed

I am Lyosha [343]

Answer:

c. remains the same, but the RPMs decrease.

Explanation:

Because there aren't external torques on the system composed by the person and the turntable it follows that total angular momentum (I) is conserved, that means the total angular momentum is a constant:

$\overrightarrow{L}=constant$

The total angular momentum is the sum of the individual angular momenta, in our case we should sum the angular momentum of the turntable and the angular momentum of a point mass respect the center of the turntable (the person)

$\overrightarrow{L_{turnatble}}+\overrightarrow{L_{person}}=constant$ (1)

The angular momentum of the turntable is:

$\overrightarrow{L_{turnatble}}=I\overrightarrow{\omega}$ (2)

with I the moment of inertia and ω the angular velocity.

The angular momentum of the person respects the center of the turntable is:

$\overrightarrow{L_{person}}=\overrightarrow{r}\times m\overrightarrow{v}$ (3)

with r the position of the person respects the center of the turntable, m the mass of the person and v the linear velocity

Using the fact $v=\omega r$ :

$\overrightarrow{L_{person}}=\overrightarrow{r}\times rm\overrightarrow{\omega}$ (3)

By (3) and (2) on (1) and working only the magnitudes (it's all that we need for this problem):

$I\omega+r^{2}m\omega=constant$

$\omega(I+r^{2}m)=constant$

Because the equality should be maintained, if we increase the distance between the person and the center of the turntable (r), the angular velocity should decrease to maintain the same constant value because I and m are constants, so the RPM's (unit of angular velocity) are going to decrease.

4 0

3 years ago

The x and y components of vector S are -30.0 m and +40.0 m, respectively. Find the magnitude of S and the angle between the dire

34kurt

Answer:

The given vector can be represented in unit vector as

$\overrightarrow{w}=-30\widehat{i}+40\widehat{j}$

The magnitude of any vector $\overrightarrow{r}=u\widehat{i}+v\widehat{j}$ is given by

$|w|=\sqrt{u^{2}+v^{2}}$

Applying values we get

$|w|=\sqrt{-30^{2}+40^{2}}\\\\|r|=50$

We know that positive x axis in vertorial form is represented as

$\overrightarrow{r}=\widehat{i}$

taking dot product of both the vector's we get

$\overrightarrow{r}.\overrightarrow{w}=|r||w|cos(\theta )\\\\\therefore cos(\theta )=\frac{(-30\widehat{i}+40\widehat{j}).\widehat{i}}{50}\\\\\therefore \theta =cos^{-1}(\frac{-30}{50})=126.86^{o}$

5 0

3 years ago

Read 2 more answers

When four people with a combined mass of 310 kg sit down in a 2000-kg car, they find that their weight compresses the springs an

luda_lava [24]

Answer:

Explanation:

F=kx

x=F/k

F=2000 kg

x=100 cm=9*10^-3

effective spring constant=k=F/x

k=2000/9*10^-3=2.2*10^-5

now frequency

f=1/2π√k/m

f=1/2*3.14√2.2*10^-5/310

f=1/6.28√7.097*10^-8

f=1/6.28*2.7*10^-4

f=0.16*2.7*10^-4

f=4.32*10^-5

4 0

3 years ago

Water is moving at a velocity of 2.00 m/s through a hose with an Internal diameter of 1.60 cm. What is the volume flow rate at t

Leya [2.2K]

Answer:

15 m/s

Explanation:

3 0

3 years ago

I'll mark brainiest if you help me

Butoxors [25]

Question 4 is true, question 5 is B.

5 0

3 years ago