1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MAXImum [283]
3 years ago
9

A box of books weighing 319 N is shoved across the floor by a force of 485 N exerted downward at an angle of 35 degres below the

horizontal.a) If the coeficent of friction between the box and the floor is 0.57, how long does it take to move the box 4 meters, starting from rest?b) If If the coeficent of friction between the box and the floor is 0.75, how long does it take to move the box 4 meters, starting from rest?
Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Let <em>w</em>, <em>n</em>, <em>p</em>, and <em>f</em> denote the magnitudes of the 4 forces acting on the box.

• <em>w</em> = <u>w</u>eight = 319 N

• <em>n</em> = <u>n</u>ormal force

• <em>p</em> = <u>p</u>ushing force = 485 N

• <em>f</em> = <u>f</u>riction = <em>µ</em> <em>n</em>, where <em>µ</em> is the coefficient of static friction

The net force on the box points in the direction that the box moves, which is to the right. In particular, this means the box is vertically in equilibrium. Split up the vectors into their vertical and horizontal components, and apply Newton's second law. (I take up and right to be the positive vertical and horizontal directions, respectively.)

• vertical:

<em>p</em> sin(-35°) + <em>n</em> - <em>w</em> = 0

and solving for <em>n</em>,

- (485 N) sin(35°) + <em>n</em> - 319 N = 0

<em>n</em> ≈ 597 N

• horizontal:

<em>p</em> cos(-35°) - <em>f</em> = <em>m</em> <em>a</em>

where <em>a</em> is the magnitude of the net acceleration on the box. Solve for <em>a</em>. Since <em>f</em> = <em>µ</em> <em>n</em> and <em>m</em> = <em>w</em> / <em>g</em> (where <em>g</em> = 9.80 m/s² is the mag. of the acc. due to gravity) we get

<em>p</em> cos(35°) - <em>µ</em> <em>n</em> = (<em>w</em> / <em>g</em>) <em>a</em>

(485 N) cos(35°) - <em>µ</em> (597 N) = (319 N) / (9.80 m/s²) <em>a</em>

<em>a</em> ≈ (12.2 - 18.3 <em>µ</em>) m/s²

(a) If <em>µ</em> = 0.57, then the net acceleration on the box is

<em>a</em> ≈ (12.2 - 18.3 • 0.57) m/s² ≈ 1.75 m/s²

so that the time <em>t</em> required to move the box 4 m is

4 m = 1/2 <em>a</em> <em>t </em>²

<em>t</em> ≈ √((8 m) / (1.75 m/s²))

<em>t</em> ≈ 2.14 s

(b) The box does not move.

If <em>µ</em> = 0.75, then

<em>a</em> = (12.2 - 18.3 • 0.75) m/s² ≈ -1.55 m/s²

but a negative acc. here means the applied acc. points *opposite* the direction of movement, thus making the box move backward which doesn't make sense. The coefficient of friction is too large for the given applied force to get the box moving. With <em>µ</em> = 0.75, the frictional force to overcome has mag. <em>f</em> ≈ 448 N. But the given push contributes a horizontal force of (485 N) cos(-35°) ≈ 397 N. This mag. needs to be increased in order to get the box moving.

You might be interested in
Help me, Ive been stuck for 15 minutes
natita [175]
The answer is b) venus because the period rotation is also referred to as a day so if venus’ period of rotation is 243 [earth] days and its year is 225 [earth] days, then the period of rotation is longer.
5 0
2 years ago
Please help on this one?
diamong [38]

Answer:

ITS C

Explanation:

7 0
2 years ago
Light could be thought of as a stream of tiny particles discharged by _______ objects that travel in straight paths. *
Gelneren [198K]

Answer: Light could be thought of as a stream of tiny particles discharged by luminous objects that travel in straight paths.

Explanation:

We can define "radiation" as the transmision of energy trough waves or particles.

Particularly, light is a form of electromagnetic radiation, so the "tiny particles" of light are discharged by a radiating object, particularly we can be more explicit and call it a luminous object, in this way we are being specific about the nature of the radiation of the object.

5 0
3 years ago
What is the instantaneous speed at 5 seconds? (remember s=d/t)
TEA [102]
5 seconds is a poor time to ask about, because the speed abruptly changes at exactly 5 seconds.

Up until that time, the speed has been 1 m/s. And then, at exactly 5 seconds, it becomes zero.
_________

It's also a poor question because speed is calculated from the distance covered, but the graph shows displacement, not distance. You can't really tell the distance covered from a displacement graph. For example, if an object happens to be moving in a circle around the place where it started, then the total distance covered keeps increasing, but its displacement is constant.
4 0
3 years ago
Read 2 more answers
An athlete jumping vertically on a trampoline leaves the surface with a velocity of 8.5 m/s upward. what maximum height does she
Mumz [18]
<span>Her center of mass will rise 3.7 meters. First, let's calculate how long it takes to reach the peak. Just divide by the local gravitational acceleration, so 8.5 m / 9.8 m/s^2 = 0.867346939 s And the distance a object under constant acceleration travels is d = 0.5 A T^2 Substituting known values, gives d = 0.5 9.8 m/s^2 (0.867346939 s)^2 d = 4.9 m/s^2 * 0.752290712 s^2 d = 3.68622449 m Rounded to 2 significant figures gives 3.7 meters. Note, that 3.7 meters is how much higher her center of mass will rise after leaving the trampoline. It does not specify how far above the trampoline the lowest part of her body will reach. For instance, she could be in an upright position upon leaving the trampoline with her feet about 1 meter below her center of mass. And during the accent, she could tuck, roll, or otherwise change her orientation so she's horizontal at her peak altitude and the lowest part of her body being a decimeter or so below her center of mass. So it would look like she jumped almost a meter higher than 3.7 meters.</span>
8 0
3 years ago
Other questions:
  • A 10.0-cm-diameter and a 20.0-cm-diameter charged ring are arranged concentrically (so they share the same axis). Assume both ar
    6·1 answer
  • How to describe the motion of an object that has an acceleration of 0 m/s
    11·1 answer
  • Which of the following statement is true?
    14·1 answer
  • The range of electromagnetic waves placed in a certain order is called the
    9·2 answers
  • A scientist observed the formation of hundreds of maggots and many flies on a rotting meat slice exposed to the environment. Wha
    12·1 answer
  • a boy runs from his house to school at speed 5m/s on a straight road and returns with speed of 10m/s.The distance between the ho
    8·1 answer
  • A battery with an emf of 24.0 V is connected to a resistive load. If the terminal voltage of the battery is 16.1 V and the curre
    9·1 answer
  • A 30 kg student drops down from the monkey bars. The acceleration due to gravity is -9.8 m/s^2. Neglecting air drag, what is the
    6·1 answer
  • In 1985, Said Aouita set the world record for the 1500m race in a time of 3 minute 29.46 second ? What was his average speed ?
    14·1 answer
  • An Electric Field does 25 mJ of work to move a +7.4 μC charge from one point to another. What is the potential difference betwee
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!