All categories

2 years ago

Before lava reaches the surface the molten material is called what

Physics

2 answers:

matrenka [14]2 years ago

7 0

Before lava reaches the surface, the molten material is called magma

algol [13]2 years ago

5 0

<span>Before lava reaches the surface the molten material is called ___.

Answer: Magma

-I hope this helped. :)</span>

You might be interested in

A rock is suspended by a light string. When the rock is in air, the tension in the string is 43.8 N . When the rock is totally i

sergeinik [125]

Answer:

Density of unknown liquid is $2047 kg/m^3$

Explanation:

When rock is suspended in air then the weight of the rock is counter balanced by the tension force in the string

So here we have

$T = mg = 43.8 N$

now when the rock is immersed in water then the tension in the string is and buoyancy force due to water is counter balanced by the weight of the object

so here we have

$T_1 + F_b = mg$

$31.3 + F_b = 43.8$

$F_b = 43.8 - 31.3 = 12.5 N$

now we have

$(1000)V(9.81) = 12.5$

$V = 1.27 \times 10^{-3} m^3$

now when the rock is immersed into other liquid then we have

$T_2 + F_b' = mg$

$18.3 + F_b' = 43.8$

$F_b' = 25.5 N$

now we have

$\rho(1.27 \times 10^{-3})(9.81) = 25.5$

$\rho = 2047 kg/m^3$

4 0

2 years ago

Find the emitted power per square meter of peak intensity for a 3000 k object that emits thermal radiation.

Aleksandr [31]

According to Stefan-Boltzmann Law, the thermal energy radiated by a radiator per second per unit area is proportional to the fourth power of the absolute temperature. It is given by;
P/A = σ T⁴ j/m²s
Where; P is the power, A is the area in square Meters, T is temperature in kelvin and σ is the Stefan-Boltzmann constant, ( 5.67 × 10^-8 watt/m²K⁴)
Therefore;
Power/square meter = (5.67 × 10^-8) × (3000)⁴
= 4.59 × 10^6 Watts/square meter

8 0

2 years ago

Read 2 more answers

A football player punts the ball from the ground at a 65.0° angle above the horizontal. If the ball stays in the air for a total

maw [93]

Answer: $V_{0,x } = 297.7 \frac{m}{s}\\V_{0,y } = 637 \frac{m}{s}$

Explanation:

Hi!

We define the point (0,0) as the intial position of the ball. The initial velocity is $(V_{0,x}, V_{0,y})$

The motion of the ball in the horizontal direction (x) has constant velocity, because there is no force in that direction. :

$x(t) = V_{0,x}t$

In the vertical direction (y), there is the downward acceleration g of gravity:

$y(t) = -gt^2 + V_{0,y}t$

(note the minus sign of acceleration, because it points in the negative y-direction)

When the ball hits the ground, at t = 65s, y(t = 65 s) = 0. We use this to find the value of the initial vertical velocity:

$0 = t(-gt + V_{0,y})\\V_{0,y} = gt = 9.8 \frac{m}{s^2} 65 s = 637 \frac{m}{s}$

We used that g = 9.8 m/s²

To find the horizonttal component we use the angle:

$\tan(65\º) = \frac{V_{y,0}}{V_{x,0}} = 2.14\\V_{x,0} = 297.7\frac{m}{s}$

5 0

2 years ago

A plate moves 2 km over a million years. A quarter of the way through this million-year timespan (at 250,000 years), the velocit

Dvinal [7]

The instantaneous velocity of the plate at 250,000 years is 5 mm/year.

The finite velocity of the plate for the entire million-year timespan is 2 mm/year.

<h3>Instantaneous velocity </h3>

The instantaneous velocity is the rate of change of displacement with time. It measures the velocity at a specific period of time.

The instantaneous velocity of the plate at 250,000 years is 5 mm/year.

<h3>Finite velocity</h3>

The finite velocity of the plate for the entire million-year timespan is calculated as follows;

$v = \frac{2 \ km}{1 \times 10^6 \ year} = \frac{2 \times 10^6 \ mm}{1 \times 10^6 \ year} = 2 \ mm/year$

Learn more about instantaneous velocity here: brainly.com/question/2234298

5 0

2 years ago

Which statement is true for particles of the medium of an earthquake P-wave? A.THEY VIBRATE IN A DIRECTION PARALLEL TO THAT OF T

ser-zykov [4K]

<span>B. This is because P-waves is shorthand for Pressure-waves. Pressure waves compress and stretch along the direction of motion.</span>

8 0

2 years ago