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Dimas [21]
3 years ago
14

Please help me solve question 5.) with the letters a) & b)

Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer:

Step-by-step explanation:

5.(a)

x²+6x-15=0

x=\frac{-6\pm\sqrt{36+4*15}}{2*1}\\x=\frac{-6\pm\sqrt{36+60} }{2}\\x=\frac{-6\pm\sqrt{96} }{2}\\x=\frac{-6\pm4\sqrt{6} }{2}\\x=-3\pm2\sqrt{6}

(b)

4x²-8x-1=0

x=\frac{8\pm\sqrt{64+4*4}}{2*4}\\x=\frac{8\pm\sqrt{80}}{8}\\x=\frac{8\pm 4\sqrt{5} }{8}\\x=\frac{2\pm\sqrt{5}}{2}

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mart [117]

Answer:

Part A

Each time you press F9 on your keyboard, you see an alternate life for Jacob, with his status for each age range shown as

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4 years ago
The area of a rectangular wall of a barn is 85 square feet. Its length is 12 feet longer than the width. Find the length and wid
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Answer:

Length = 17 feet, Width = 5 feet

Step-by-step explanation:

Given:

The area of a rectangular wall of a barn is 85 square feet.

Its length is 12 feet longer than the width.

Question asked:

Find the length and width of the wall of the barn.

Solution:

Let width of a rectangular wall of a barn = x

<u>As length is 12 feet longer than the width.</u>

Length of a rectangular wall of a barn = 12+x

As we know:

Area\ of\ rectangle=length\times breadth

85=(12+x)x\\\\85=12x+x^{2} \\

Subtracting both sides by 85

x^{2} +12x-85=0\\x^{2} +17x-5x-85=0\\Taking\ common\\x+(x+17)-5x(x+17)=0\\(x+17)(x-5)=0\\x+17=0, x-5=0\\x=-17,x=5

As width can never be in negative, hence  width of a rectangular wall of a barn = x = 5 feet

Length of a rectangular wall of a barn = 12+x=12+5=17\ feet

Therefore, length and width of the wall of the barn is 17 feet and 5 feet respectively.

                 

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So if a shape has 7 sides it will have 7 lines of symmetry.

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Answer:

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