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malfutka [58]
3 years ago
13

Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

Mathematics
2 answers:
Fantom [35]3 years ago
5 0

Answer:

its the 3cm i did it

Step-by-step explanation:

Ghella [55]3 years ago
4 0

Step 1) Find the area of the faces

There are 4 triangular faces on this rectangular pyramid. In this case, they are all the same, because each triangle has the same base and height. We will find the area of 1 triangle and multiply it by 4 to find the area of all of the triangular faces.

A = 1/2 x 3 x 2

A = 1/2 x 6

A = 3

3 x 4 = 12

A = 12 cm^2

Step 2) Find the area of the base

The base has a length of 2 cm and a width of 2 cm. We can find the area of the base by multiplying the length and width because the base is a rectangle.

A = 2 x 2

A = 4 cm^2

Step 3) Add the areas together

Now, we need to add the area of the faces and the area of the base together to find the surface area.

A = 12 + 4

A = 16 square centimeters

Hope this helps! :)

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In total it rained 96.6cm that year but on average it rained 100cm that year.
You would multiply 8.05 times the #of momths which is twelve.
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Compare the rates of change of the following items.
vladimir1956 [14]

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2 years ago
A TV show, Lindsay and Tobias, recently had a share of 20, meaning that among the TV sets in use, 20% were tuned to that show. A
kati45 [8]

Answer:

8.6% probability that none of the households are tuned to Lindsay and Tobias.

There is a 91.4% probability that at least one household is tuned to Lindsay and Tobias.

There is a 32.2% probability that at most one household is tuned to Lindsay and Tobias.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are watching the TV show, or they are not. This means that we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 11, p = 0.20

Find the probability that none of the households are tuned to Lindsay and Tobias.

This is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{11,0}.(0.20)^{0}.(0.80)^{11} = 0.086

8.6% probability that none of the households are tuned to Lindsay and Tobias.

Find the probability that at least one household is tuned to Lindsay and Tobias.

Either no household is tuned, or at least one is tuned. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.086 = 0.914

There is a 91.4% probability that at least one household is tuned to Lindsay and Tobias.

Find the probability that at most one household is tuned to Lindsay and Tobias.

This is

P(X \leq 1) = P(X = 0) + P(X = 1)

P(X = 1) = C_{11,1}.(0.20)^{1}.(0.80)^{10} = 0.236

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.086 + 0.236 = 0.322

There is a 32.2% probability that at most one household is tuned to Lindsay and Tobias.

8 0
3 years ago
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