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3 years ago

Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

Mathematics

2 answers:

Fantom [35]3 years ago

5 0

Answer:

its the 3cm i did it

Step-by-step explanation:

Ghella [55]3 years ago

4 0

Step 1) Find the area of the faces

There are 4 triangular faces on this rectangular pyramid. In this case, they are all the same, because each triangle has the same base and height. We will find the area of 1 triangle and multiply it by 4 to find the area of all of the triangular faces.

A = 1/2 x 3 x 2

A = 1/2 x 6

A = 3

3 x 4 = 12

A = 12 cm^2

Step 2) Find the area of the base

The base has a length of 2 cm and a width of 2 cm. We can find the area of the base by multiplying the length and width because the base is a rectangle.

A = 2 x 2

A = 4 cm^2

Step 3) Add the areas together

Now, we need to add the area of the faces and the area of the base together to find the surface area.

A = 12 + 4

A = 16 square centimeters

Hope this helps! :)

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The The point (2,6) is on the line given by which equation below?

maria [59]

Answer:

A y = 3x

Step-by-step explanation:

We can check each line to see if the point is on it

A y = 3x 6 = 2*3 6=6 this is true so the point is one the line

B y = 4-x 6 = 2-4 6 = -2 false

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3 years ago

Segment FG begins at point F(-2, 4) and ends at point G (-2, -3). Segment FG is translated by (x, y) → (x – 3, y + 2) and then r

Mariana [72]

Answer:

The length of the segment F'G' is 7.

Step-by-step explanation:

From Linear Algebra we define reflection across the y-axis as follows:

$(x',y')=(-x, y)$ , $\forall\, x, y\in \mathbb{R}$ (Eq. 1)

In addition, we get this translation formula from the statement of the problem:

$(x',y') =(x-3,y+2)$ , $\forall \,x,y\in \mathbb{R}$ (Eq. 2)

Where:

$(x, y)$ - Original point, dimensionless.

$(x', y')$ - Transformed point, dimensionless.

If we know that $F(x,y) = (-2, 4)$ and $G(x,y) = (-2,-3)$ , then we proceed to make all needed operations:

Translation

$F''(x,y) = (-2-3,4+2)$

$F''(x,y) = (-5,6)$

$G''(x,y) = (-2-3,-3+2)$

$G''(x,y) = (-5,-1)$

Reflection

$F'(x,y) = (5, 6)$

$G'(x,y) = (5,-1)$

Lastly, we calculate the length of the segment F'G' by Pythagorean Theorem:

$F'G' = \sqrt{(5-5)^{2}+[(-1)-6]^{2}}$

$F'G' = 7$

The length of the segment F'G' is 7.

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2 years ago

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Elza [17]

Answer:

B)7+n

Step-by-step explanation:

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Mamont248 [21]

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