Answer:
Explanation:
Considering the flow of mercury in a tube:
When it comes to laminar flow of mercury, the thermal entry length is quite smaller than the hydrodynamic entry length.
Also, the hydrodynamic and thermal entry lengths which is given as DLhRe05.0= for the case of laminar flow. It should be noted however, that Pr << 1 for liquid metals, and thus making the thermal entry length is smaller than the hydrodynamic entry length in laminar flow, like I'd stated in the previous paragraph
Answer:
Using the equation of continuity:
A
1
v
1
=
A
2
v
2
0.08
(
10
)
=
A
2
(
225
)
A
2
=
3.55
×
10
−
3
m
2
Q
2
=
A
2
v
2
Q
2
=
3.55
×
10
−
3
×
225
Q
2
=
0.798
m
3
/
s
Explanation:
Steady Flow Energy Equation:
The steady flow energy equation is a representation of the first law of thermodynamics. It is the conservation of energy law for an open system. A nozzle is an open system in the context of thermodynamics. It is used to produce a high velocity by reducing its pressure.
The steady flow energy equation can be given by the following formula:
h
1
+
1
2
v
2
1
+
g
z
1
+
q
=
h
2
+
1
2
v
2
2
+
g
z
2
+
w
where 'h' is enthalpy, 'v' is velocity, 'z' is height, 'q' is the heat and 'w' is work.
h
=
C
p
d
T
Answer and Explanation:
Given:
initial temp,
T
1
=
400
0
C
initial Pressure,
p
1
=
800
k
P
a
Initial Velocity,
v
1
=
10
m
/
s
Final temp,
T
2
=
300
0
C
Final Pressure,
p
2
=
200
k
P
a
Rate of heat loss, Q = 25 KW
Inlet Area,
A
1
=
800
c
m
2
As per the steady flow energy equation:
h
1
+
1
2
v
2
1
+
g
z
1
+
q
=
h
2
+
1
2
v
2
2
+
g
z
2
+
w
Since, there is external work, w= 0. Also, consider there is a negligible change in KE.
h
1
+
1
2
v
2
1
+
q
=
h
2
+
1
2
v
2
2
h
1
−
h
2
+
1
2
v
2
1
+
q
=
1
2
v
2
2
C
p
(
T
1
−
T
2
)
+
1
2
(
10
)
2
+
25000
=
1
2
v
2
2
2
(
400
−
300
)
+
50
+
25000
=
1
2
v
2
2
2
(
400
−
300
)
+
50
+
25000
=
1
2
v
2
2
25250
=
1
2
v
2
2
v
2
≈
225
which is the answer.
Using the equation of continuity:
A
1
v
1
=
A
2
v
2
0.08
(
10
)
=
A
2
(
225
)
A
2
=
3.55
×
10
−
3
m
2
Now, volume flow rate,
Q
2
=
A
2
v
2
Q
2
=
3.55
×
10
−
3
×
225
Q
2
=
0.798
m
3
/
s
Answer:
The right answer is (d)
Explanation:
The pressure drop in smooth pipes with laminar flow is determined by the resistance of the fluid to flow, which is controlled by Reynolds's number. At higher Re, higher drop. But in this case, we have no information about the speed of the fluid in each pipe, and the ipe is not related to that speed. therefore we don´t have the information to say that any of the other options are the right ones
Answer:
100 mA (1 A) because a current between 1 A - 4.3 A causes muscle contractions
Answer: -10% To + 5% Voltage.
Explanation: ThANk yOu VeRY mUCh.