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nirvana33 [79]
4 years ago
12

This is an essential safety procedure that protects workers from injury while working on or near electrical circuits and equipme

nt by locking the device and/or power source to prevent anyone from turning on the hazardous power sources while someone is performing maintenance or servicing work: Select the best option a. Shutdown b. Lockout/Tagout c. Closeout
Engineering
1 answer:
Mice21 [21]4 years ago
8 0

Answer:

Option B

Lockout/ Tagout

Explanation:

lockout and tagout is a safety procedure used in most industries and work places. This ensures that during any maintenance work, that dangerous machines are properly shut off and not able to be started up again prior to the completion of maintenance or repair work.

The procedure includes:

1. Turns off and disconnects the machinery or equipment from its energy source(s) before performing service or maintenance.

2. The authorized employee(s) either lock or tag the energy-isolating device(s) to prevent the release of hazardous energy.

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Technician A says that the mainline pressure is usually higher in manual first gear than it is when the gear selector is in the
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Answer:

Technician A & B

Explanation:

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4 years ago
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In which of the following systems are all of the forces acting on the exact same line of action?
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Collinear system refers to the type which involves all of the forces acting on the exact same line of action .

<h3>What is Force?</h3>

This is referred to an influence which is capable of altering the motion of an object or particle.

Collinear system has forces which acts on the same line. If X, Y and Z are collinear then m X Y = m Y Z ( = m X Z ) .

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7 0
2 years ago
A series resistive circuit has two resistors. R1 is 570 ohms and R2 is 560 ohms.
ZanzabumX [31]

Answer:

10.203 Volts

Explanation:

For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.

First, we need to find the voltage in the circuit.  To do this, we need to find the total resistance of the circuit.  When two resistors are in series, you sum the resistance.  So we can say the following:

R_Total = R1 + R2

R_Total = 570 Ω + 560 Ω

R_Total = 1130 Ω

Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.

V_Total = I_Total * R_Total

V_Total = 17.9 mA * 1130 Ω

V_Total = 20.227 V

Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more.  Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).

V_Total = V_1 + V_2

V_Total = V_1 + I_2*R2

V_Total - I_2*R2 = V_1

20.227 V - (17.9 mA * 560 Ω) = V_1

20.227 V - (10.024 V) = V_1

10.203 V = V_1

Hence, the voltage drop across R1 is 10.203 Volts.

Cheers.

3 0
3 years ago
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