Answer:
The diameter is 50mm
Explanation:
The answer is in two stages. At first the torque (or twisting moment) acting on the shaft and needed to transmit the power needs to be calculated. Then the diameter of the shaft can be obtained using another equation that involves the torque obtained above.
T=(P×60)/(2×pi×N)
T is the Torque
P is the the power to be transmitted by the shaft; 40kW or 40×10³W
pi=3.142
N is the speed of the shaft; 250rpm
T=(40×10³×60)/(2×3.142×250)
T=1527.689Nm
Diameter of a shaft can be obtained from the formula
T=(pi × SS ×d³)/16
Where
SS is the allowable shear stress; 70MPa or 70×10⁶Pa
d is the diameter of the shaft
Making d the subject of the formula
d= cubroot[(T×16)/(pi×SS)]
d=cubroot[(1527.689×16)/(3.142×70×10⁶)]
d=0.04808m or 48.1mm approx 50mm
Hi
Acetylene and propane
I hope this help you!
Answer:
The amount of cargo the plane can carry is 8707.89 N
Explanation:
The surface area of the wings facing the air = 30×6×2 × sin(2.5) = 15.7 m²
The speed of the plane 550 km/h = 152.78 m/s
The volume of air cut through per second = 15.7 × 152.78 = 2399.07 m³
The mass of air = Volume × Density = 2399.07 × 0.37 = 887.65 kg
Weight of air = Mass × Acceleration due to gravity = 887.65 × 9.81 = 8707.89 N
Given that the plane is already airborne, the additional cargo the plane can carry is given by the available lift force of the plane.
The amount of cargo the plane can carry = 8707.89 N
Answer:
Explanation:
The detailed analysis, with free body diagram and step by step calculations with appropriate substitution is as shown in the attached files.
Answer:
180 x 60 inches
Width = 60 inches
Length = 180 inches
Explanation:
Given
Let L = Length
W = Width
P = Perimeter
Length = 3 * Width
L = 3W
Perimeter of Brass = 480 inches
P = 480
Perimeter is given as 2(L + W);
So, 2 (L + W) = 480
L + W = 480/2
L + W = 240
Substitute 3W for L; so,
3W + W = 240
4W = 240
W = 240/4
W = 60 inches
L = 3W
L = 3 * 60
L = 180 inches