Answer:
See Explanation.
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra II</u>
- Log/Ln Property:

<u>Calculus</u>
Derivatives
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Chain Rule: ![\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%20%3Df%27%28g%28x%29%29%20%5Ccdot%20g%27%28x%29)
Derivative of Ln: ![\frac{d}{dx} [ln(u)] = \frac{u'}{u}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bln%28u%29%5D%20%3D%20%5Cfrac%7Bu%27%7D%7Bu%7D)
Step-by-step explanation:
<u>Step 1: Define</u>

<u>Step 2: Differentiate</u>
- Rewrite:

- Rewrite [Ln Properties]:

- Differentiate [Ln/Chain Rule/Basic Power Rule]:

- Simplify:

- Rewrite:

- Combine:

- Reciprocate:

- Distribute:

The bearing of the individuals from each other are as indicated below;
- S45°E
- N25°E
- S65°E
- S15°E
- N45°E
- N75°E
<h3>What is bearing of Henley from Dinder?</h3>
It follows from the task content that the bearing of the individuals from each other are expected to be determined.
a) For Henley from Dinder; it follows from observation that Henley is; S45°E of Dinder's position.
b) For Dinder from Weare; it follows from observation that Dinder is; N25°E of Weare's position.
c) For Weare from Dinder; it follows from observation that Weare is; S65°E of Dinder's position.
d) For Weare from Henly; it follows from observation that Weare is; S15°E of Dinder's position.
e) For Dinder from Henly; it follows from observation that Dinder is; N45°E of Henly's position.
f) For Henly from Weare; it follows from observation that Henly is; N75°E of Weare's position.
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Answer:
B & C
Step-by-step explanation:
A proportional relationship has a proportionality constant (constant rate of change) and and must cross through the origin (or begin at (0,0). This means it's y-intercept is 0. Each of the options is a linear function. All of the functions have a constant rate of change. Only one as b=0 or 0 as the y-intercept.
B) y=4x has a constant of 4 and passes through the origin.
C) y=7x has a constant of 7 and passes through the origin.
The intital amount deposited was $18485.82.
<h3>How to find the compound interest?</h3>
If n is the number of times the interested is compounded each year, and 'r' is the rate of compound interest annually, then the final amount after 't' years would be:

An account has $26,000 after 15 years. The account received 2.3 percent interest compounded continuously.
A = 26000
R = 0.02.3


Therefore, the intital amount deposited was $18485.82.
Learn more about compound interest here:
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Answer:
846 m³
Step-by-step explanation:
The solid consists of a rectangular prism and a rectangular pyramid.
V = LWH + (1/3)LWh
V = 9 m * 6 m * 12 m + 1/3 * 9 m * 6 m * 11 m
V = 648 m³ + 198 m³
V = 846 m³