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Fynjy0 [20]
3 years ago
6

I asked this earlier and got no answer. Will give brainliest

Mathematics
1 answer:
Virty [35]3 years ago
6 0
The area of a square is

s • s

We can also write this as

s^2

So, for any side length “s”, we can make a function, A(s), such that

A(s) = s^2

Now that we have a quadratic equation for the area of a square, let’s go ahead and solve for the side lengths of a square with a given area. In this case, 225 in^2

225 = s^2

Therefore,

s = sqrt(225)

s = 15

So, the dimensions are 15 x 15 in

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Problem1 The behavior of a physical system can be described by the following first order differential equation: dy/dt=2y +t^2
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Answer:

y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}.

Step-by-step explanation:

Using first order linear differential equation:

\dfrac{\mathrm{d} y}{\mathrm{d} t} = 2y + t^2

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y = \dfrac{1}{e^{-2t}}(\int t^2dt+ c )

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hence the solution is

y = \dfrac{t^3e^{2t}}{3}+Ce^{2t}

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