Answer:
The correct option is this: DECREASING THE TEMPERATURE.
Explanation:
During the process of chemical reaction, the reacting molecules typically move about randomly in the reacting vessels colliding with one another and with the wall of the container. The rate of movement of the reacting particles can be reduced by decreasing the temperature of the reaction. If the temperature is reduced, the particles will lose kinetic energy and thus, they will move more slowly and collide less often with one another.
Equation for half-lives:
Nt = No x (1/2)^n
No = initial amount
Nt = final amount after t years
n = number of half lives = t/(single half-life)
t = years
Nt = 3/12 = 0.25
No = 12/12 = 1.00
n = t/(24400)
3/12 = (12/12) x (0.5)^(t/24400)
(0.25) = 1.00 x (0.5)^(t/24400)
0.25/1.00 = 0.5^(t/24400)
ln(0.25) = ln(0.5^(t/24400))
ln(0.25) = (t/24400)*ln(0.5)
ln(0.25)/ln(0.5) = (t/24400)
2 = t/24400
2*24400 = t
t = 48800 yrs
answer is <u>t = 48,800 yrs</u>
Answer:
after 28.8 years 250 g of Pu-241 still remaining
Explanation:
Given data:
Total amount of Pu-241 = 1000 g
Half life = 14.4 years
Amount remaining after 28.8 years = ?
Solution:
Number of half lives = T elapsed / half life
Number of half lives = 28.8 years / 14.4 years
Number of half lives = 2
At time zero = 1000 g
At first half life = 1000 g/ 2 = 500 g
At second half life = 500 g/2 = 250 g
So after 28.8 years 250 g of Pu-241 still remaining.
<u>Answer:</u> The correct answer is Option C.
<u>Explanation:</u>
We are given some polyatomic ions with their oxidation states. Polyatomic ions are defined as the ions which are formed from more than 2 atoms.
We need to find out the chemical formula for ammonium phosphate.
For this, the polyatomic ions used are:
Ammonium ion - 
Phosphate ion - 
By using criss-cross method, the oxidation state of the ions are exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.
Thus, the chemical formula for this compound is 
Hence, the correct answer is Option C.
2 hydrogens and an Oxygen
