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-Dominant- [34]
2 years ago
6

Solve

Mathematics
2 answers:
PIT_PIT [208]2 years ago
5 0

A cylinder of radius r cm and height h cm has a curved surface area A cm². Where –

  • A = 2πrh cm²

a) We are asked to find formula for h.

\qquad\purple{ \bf  \longrightarrow A=2 \pi rh }

First, overturn the equation

\qquad\sf  \longrightarrow 2 \pi rh =A

Divide both sides by 2πr

\qquad\sf  \longrightarrow \dfrac{2\pi rh}{2\pi r } = \dfrac{A}{2\pi r}

\qquad\sf  \longrightarrow \dfrac{\cancel{2 \pi r }h}{\cancel{2\pi r} } = \dfrac{A}{2\pi r}

\qquad\purple{\bf  \longrightarrow h = \dfrac{A}{2 \pi r }}

b) Again, we are given –

  • Curved surface area, A = 93 cm²
  • Radius, r = 2.5 cm
  • π = 3.1

\qquad\qquad\quad\underline{\sf{Substituting \ Values \ :}}

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━

\qquad\bf  \longrightarrow h = \dfrac{A}{2\pi r  }

\qquad\sf  \longrightarrow h = \dfrac{93}{2 \times 3.1 \times 2.5   }

\qquad\sf  \longrightarrow h = \dfrac{93}{15.5}

\qquad\sf  \longrightarrow h =\cancel{ \dfrac{93}{15.5}}

\qquad\pink{ \bf  \longrightarrow h = 6\: cm }

  • Henceforth, height of the cylinder is 6 cm.
kobusy [5.1K]2 years ago
5 0

The Answer is Letter A.....

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\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
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\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
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\\ \quad \\
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f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
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\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
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with that template in mind, let's see    \bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
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&\quad \uparrow \\
&\quad  B
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