Answer:
Step-by-step explanation:
\text{Area of a Triangle}\rightarrow \text{S.A.S.}
Area of a Triangle→S.A.S.
\text{Area}=\frac{1}{2}ab\sin C
Area=
2
1
absinC
From reference sheet.
\text{Area}=\frac{1}{2}(64)(83)\sin 168
Area=
2
1
(64)(83)sin168
Plug in values.
\text{Area}\approx552.213\approx 552
Area≈552.213≈552
Evaluate and round.
Answer: 552
This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :
![(Hypotenuse)^2=(Perpendicular)^2+(Base)^2](https://tex.z-dn.net/?f=%28Hypotenuse%29%5E2%3D%28Perpendicular%29%5E2%2B%28Base%29%5E2)
![(AB)^2=(AC)^2+(BC)^2](https://tex.z-dn.net/?f=%28AB%29%5E2%3D%28AC%29%5E2%2B%28BC%29%5E2)
Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.
![(AB)^2=(6)^2+(8)^2](https://tex.z-dn.net/?f=%28AB%29%5E2%3D%286%29%5E2%2B%288%29%5E2)
![AB=\sqrt{(6)^2+(8)^2}](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%286%29%5E2%2B%288%29%5E2%7D)
![AB=10ft](https://tex.z-dn.net/?f=AB%3D10ft)
Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.
Answer:
Step-by-step explanation:
No. If you reverse the prime number 23, you get 32 and that number is not a prime number.