Forensic toxicologist analyze and identify drugs that are confiscated from criminals

A 650 kg steel beam is being pulled up by a crane with a force of 7020 N. What is the upwards acceleration of the beam?

zimovet [89]

Answer: 1 m/s^2

Explanation:

n= w+ma

n= Mg+Ma

7020 = (650)(9.8)+650a

7020 = 6370+ 650a

650=650a

A= 1 m/s^2

8 0

3 years ago

Numerical problems:

Hatshy [7]

Answer:

this is answer please mark me as brainlest

Explanation:

A force of 500N acts on the area of 2.5m2; calculate the pressure

exerted,

(Ans: 200 Pa]

b. Calculate the force applied when 400 Pa of pressure is exerted by a box

of surface area 2m2.

(Ans: 800 N]

The weight of a stone is 1400N. If it exerts a pressure of 700 Pa, calculate

the area.

(Ans: 2m]

d. A force of 2000 N acts on 5m² surface area. Calculate the pressure

exerted.

(Ans: 400 Pa]

c.

7 0

3 years ago

At Alpha Centauri's surface, the gravitational force between Alpha Centauri and a 2 kg mass of hot gas has a magnitude of 618.2

sergeinik [125]

Answer:

6.86 * 10^8 m

Explanation:

Parameters given:

Mass of hot gas, m = 2 kg

Gravitational Force, F = 618.2 N

Mass of Alpha Centauri, M = 2.178 * 10^30 kg

The gravitational force between two masses (the hot gas and Alpha Centauri) , m and M, at a distance, r, given as:

F = (G*M*m) / r²

Where G = gravitational constant

Therefore,

618.2 = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / r²

=> r² = (6.67 * 10^(-11) * 2.178 * 10^30 * 2) / 618.2

r² = 4.699 * 10^17 m²

=> r = 6.86 * 10^8 m

We are told that the hot gas is on the surface of Alpha Centauri, hence, the distance between both their centers is the radius of Alpha Centauri.

The mean radius of Alpha Centauri is 6.86 * 10^8 m.

5 0

3 years ago

Read 2 more answers

A stiff wire 44.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l

Helga [31]

The magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

Explanation:

It is known that the force acting on a current carrying conductor placed in a magnetic field is

$F=BIL sin theta$

Here B is the magnetic field, I is the current flowing through the wire and L is the length of the wire which is given as 44 cm.

Since the wire is bended in the middle at right angle so the length of the two sides of the wire will be 22 cm each. Also one part is lying over z axis and another part lies in the plane of xy in the equation of line y = 2x. So the slope of this wire will be

$\frac{y}{x} =2$

This will be equal to tan θ.

So θ = tan⁻¹ (2) =63.4°

Then, the length of the wire will be written as components of i, j and k.

$L = (-22)k+(22) cos ( 63.4) i+(22) sin (63.4)j$

$L = 0.098 i+0.197 j-0.22k$

Then,

F = I (L × B)

$F = 20.5 ((0.0985 i + 0.197 j -0.22k) * (0.316 i))$

$F = 20.5 (\left[\begin{array}{ccc}i&j&k\\0.098&0.197&-0.22\\0.316&0&0\end{array}\right] )$

$F = 20.5(i(0)-j(0-(-0.22*0.316))+k(0-(0.316*0.197))) = 20.5(-0.069 j-0.062 k)$

$F = -1.415 j-1.271 k$

The magnitude of force on the wire will be

$F = \sqrt{(-1.415)^{2}+(-1.27)^{2} } = \sqrt{3.615}=1.90 N$

And the direction can be found by the tan inverse of the ratio of k component to j component of the force.

$theta = tan-1(\frac{-1.271}{-1.415})= 41.9 degrees$

So the magnitude of force acting on wire will be 1.90 N and the direction of the force acting on the wire will be 41.9 degrees below the negative y axis.

5 0

4 years ago

You are taking a picture of a giraffe that is standing far away from you. The image is just too small, so you swap the 60-mm-foc

vfiekz [6]

Explanation:

Given that, you are taking a picture of a giraffe that is standing far away from you. The image is just too small, so you swap the 60-mm-focal-length lens in your camera for a 960 mm telephoto lens such that,

$m_1=960\ mm$

$m_2=60\ mm$

We need to find the the factor with which the size of the image increases. It can be calculated by taking ratios of both $m_1\ and\ m_2$

So, $\dfrac{m_1}{m_2}=\dfrac{960}{60}$

$\dfrac{m_1}{m_2}=16$

So, the size of image increases by a factor of 16. Hence, this is the required solution.

4 0

3 years ago