X=v(initial)t+.5(a)t^2. Car B's displacement can be represented by equation x=45t. Car A can be represented by the equation x=.5(5)t^2. Plug these equations into a graphing calc and find intercept, the x value is time, the y is displacement.
True
This is due to the taking outage in into the object.
e.g. You can take a cookie from the cookie jar and add another one into it
Answer:
The speed of the train is 80 miles/hour.
Explanation:
Given:
Distance from Spokane to Seattle = 280 miles
The trip from Spokane to Seattle by train took = 3.5 hours
To find the speed of the train.
Solution:
The speed is the distance per unit time. So, to find the speed of the train we will divide the total distance of the trip by the time taken to complete the trip by the train.
Thus, the speed of the train is 80 miles/hour.
Answer:
x(t) = - 6 cos 2t
Explanation:
Force of spring = - kx
k= spring constant
x= distance traveled by compressing
But force = mass × acceleration
==> Force = m × d²x/dt²
===> md²x/dt² = -kx
==> md²x/dt² + kx=0 ------------------------(1)
Now Again, by Hook's law
Force = -kx
==> 960=-k × 400
==> -k =960 /4 =240 N/m
ignoring -ve sign k= 240 N/m
Put given data in eq (1)
We get
60d²x/dt² + 240x=0
==> d²x/dt² + 4x=0
General solution for this differential eq is;
x(t) = A cos 2t + B sin 2t ------------------------(2)
Now initially
position of mass spring
at time = 0 sec
x (0) = 0 m
initial velocity v= = dx/dt= 6m/s
from (2) we have;
dx/dt= -2Asin 2t +2B cost 2t = v(t) --- (3)
put t =0 and dx/dt = v(0) = -6 we get;
-2A sin 2(0)+2Bcos(0) =-6
==> 2B = -6
B= -3
Putting B = 3 in eq (2) and ignoring first term (because it is not possible to find value of A with given initial conditions) - we get
x(t) = - 6 cos 2t
==>