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KIM [24]
3 years ago
11

Is it possible to toss a coin 20 times and have it land heads-up 20 times? Is this likely to happen? explain.

Mathematics
2 answers:
andrey2020 [161]3 years ago
8 0
No, because the coin has 2 sides so it mostly likely wont let on heads them 20 times. Hope i helped u :)
raketka [301]3 years ago
5 0
Yes, it is possible, but very unlikely. There is two sides to a dice, so the probability of heads is 1/2 each time. (1/2)^20 would make the probability very low. So: Yes it is possible but no is is not likely.
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Solve for x, given the equation Square root of x-5+7=11
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\sqrt{x-5+7} = 11\\x-5+7 = 11^2\\x-5+7 = 121\\x + 2 = 121\\x = 119

Check the answer:

\sqrt{119-5+7} \\\sqrt{114+7} \\\sqrt{121} \\11

This answer is correct,

x = 119

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write an even number that has a 7 in the hundreds place , has an odd number in the thousands place and is multiple of 10
Serjik [45]
Even numbers end with 0,2,4,6,8

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odd in thousands place, odd numbers are 1,3,5,7,9

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50 options

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7 0
3 years ago
Tim throws darts at a dartboard that has numbers one through 20 in a bull’s-eye in the middle. 10 throws a dart 50 times, and he
Lesechka [4]

Answer:

D.) 1/5

Explanation:

Experimental probability is the ratio of the number of successes to the number of trials.

In this case, success is a bulls-eye.  Tim had 10 bulls-eyes.  The total number of trials  is 50.  This makes the experimental probability 10/50, or 1/5.

6 0
4 years ago
Read 2 more answers
2w^2-11w=-12 <br> a w=3/2 or 4<br> b w=1 or 12<br> c w=1 or 7<br> d w = 2.5 or 6
dlinn [17]
Hey mate !!
Here's your answer !!


2w^2 - 11w = -12
2w^2 -11w + 12 = 0
2w^2 - 8w - 3w + 12 = 0

2w ( w - 4) -3 ( w - 4) = 0
(2w - 3) ( w - 4) = 0

Hence

2w - 3 = 0
2w = 3
w = 3/2

w - 4 = 0
w = 4

Hence value of w are 4 and 3/2

Hope this helps!!
Cheers!!
7 0
3 years ago
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